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Black_prince [1.1K]
4 years ago
6

I’m doing this problem and I want to know if I took the correct approach?

Mathematics
2 answers:
Marrrta [24]4 years ago
8 0

Answer:

Step-by-step explanation:

yes you did, great job!

Mandarinka [93]4 years ago
5 0

Answer:

Yes you did good job

Step-by-step explanation:

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Simplify: (x+4)*(2x+5
s344n2d4d5 [400]

Answer:

2x^2+13x+20 is the simplified answer

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What us problems 6 and 7?<br>​
Sunny_sXe [5.5K]

Answer:

y=(x+7)2(2x+1)(x−4)

y=2x4+21x3−4x2−399x−196

Step-by-step explanation:

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3 years ago
Solve for x <br><br><br><br><br><br>.problem down below ​
AleksAgata [21]
A: no solution!

first, simplify each side of the equation.

3x + 5 - 10x simplifies to -7x + 5.
8 - 7x - 12 simplifies to -7x - 4.

then, add +7x on both sides of the equation to get the variable alone. if you add 7x to each side, you get left with 0.

so, that leaves 5 = -4 which is not true. so, that means there is no solution.
5 0
3 years ago
An engineer is planning a new water pipe installation. The circular pipe has a diameter of d=20\text{ cm}d=20 cmd, equals, 20, s
aivan3 [116]

Answer: The answer is 314.28 cm² (approx.).


Step-by-step explanation:  Given that an engineer is going to install a new water pipe. The diameter of this circular pipe is, d = 20 cm.

We need to find the area 'A' of the circular cross-section of the pipe.

Given, diameter of the circular section is

\textup{d}=20~\textup{cm}.

So, the radius of the circular cross-section will be

\textup{r}=\dfrac{\textup{d}}{2}=\dfrac{20}{2}=10~\textup{cm}.

Therefore, cross-sectional area of the pipe is

\textup{A}=\pi \textup{r}^2=\dfrac{22}{7}(10)^2=\dfrac{2200}{7}=314\dfrac{2}{7}=314.28~.~.~.~\textup{cm}^2.

Thus, the answer is 314.28 cm² (approx.).

4 0
4 years ago
|BRAINLIEST|
Mekhanik [1.2K]

Answer:

<em>t</em><em>h</em><em>e</em><em> </em><em>c</em><em>o</em><em>r</em><em>r</em><em>e</em><em>c</em><em>t</em><em> </em><em>a</em><em>n</em><em>s</em><em>w</em><em>e</em><em>r</em><em> </em><em>i</em><em>s</em><em> </em><em>C</em><em> </em><em>1</em><em>/</em><em>3</em><em>2</em><em> </em><em>I</em><em>b</em>

Step-by-step explanation:

hope it helps

3 0
4 years ago
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