All categories

3 years ago

I’m doing this problem and I want to know if I took the correct approach?

Mathematics

2 answers:

Marrrta [24]3 years ago

8 0

Answer:

Step-by-step explanation:

yes you did, great job!

Mandarinka [93]3 years ago

5 0

Answer:

Yes you did good job

Step-by-step explanation:

You might be interested in

A simulation was conducted using 10 fair six-sided dice, where the faces were numbered 1 through 6. respectively. All 10 dice we

kompoz [17]

Answer:

C) a sample distribution of a sample mean with n = 10

$\mu_{{\overline}{X}} = 3.5$

and $\sigma_{{\overline}{Y}} = 0.38$

Step-by-step explanation:

Here, the random experiment is rolling 10, 6 faced (with faces numbered from 1 to 6) fair dice and recording the average of the numbers which comes up and the experiment is repeated 20 times.So, here sample size, n = 20 .

Let,

$X_{ij}$ = The number which comes up on the ith die on the jth trial.

∀ i = 1(1)10 and j = 1(1)20

Then,

$E(X_{ij})$ = $\frac {1 + 2 + 3 + 4 + 5 + 6}{6}$

= 3.5 ∀ i = 1(1)10 and j = 1(1)20

and,

$E(X^{2}_{ij}$ = $\frac {1^{2} + 2^{2} + 3^{2} + 4^{2} + 5^{2} + 6^{2}}{6}$

= $\frac {1 + 4 + 9 + 16 + 25 + 36}{6}$

= $\frac {91}{6}$

$\simeq$ 15.166667

so, $Var(X_{ij}$ = $(E(X^{2}_{ij} - {(E(X_{ij})}^{2})$

$\simeq 15.166667 - 3.5^{2}$

= 2.91667

and $\sigma_{X_{ij}}$ = $\sqrt {2.91667}[/tex [tex]\simeq 1.7078261036$

Now we get that,

$Y_{j} = \frac {\sum_{j = 1}^{20}X_{ij}}{20}$

We get that $Y_{j}'s$ are iid RV's ∀ j = 1(1)20

Let, ${\overline}{Y} = \frac {\sum_{j = 1}^{20}Y_{j}}{20}$

So, we get that $E({\overline}{Y}) = E(Y_{j})$

= $E(X_{ij}$ for any i = 1(1)10

= 3.5

and,

$\sigma_{({\overline}{Y})} = \frac {\sigma_{Y_{j}}}{\sqrt {20}} = \frac {\sigma_{X_{ij}}}{\sqrt {20}} = \frac {1.7078261036}{\sqrt {20}} [tex]\simeq 0.38$

Hence, the option which best describes the distribution being simulated is given by,

C) a sample distribution of a sample mean with n = 10

$\mu_{{\overline}{X}} = 3.5$

and $\sigma_{{\overline}{Y}} = 0.38$

6 0

2 years ago

II The small capillaries in the lungs are in close contact with the alveoli. A red blood cell takes up oxygen during the 0.5s th

dangina [55]

The diffusion time of the red blood cell to take oxygen through the membrane is 25uS.

The small capillaries in the lungs are in close contact and it takes a red blood cell 0.5 seconds to squeeze through the capillary.

The diffusion time for the oxygen across the 1 um thick membrane separating the air is given by,

t = x²/2D

Where,

t is the diffusion time,

x is the thickness of the membrane,

D is the diffusion coefficient.

Putting values,

t = (1 x 10⁻⁹)²/2 x 2 x 10⁻¹¹

t = 10⁻⁷/4

t = 25 x 10⁻⁹ seconds.

t = 25 uS.

so, the diffusion time is 25uS.

To know more about Diffusion, visit,

brainly.com/question/94094

#SPJ4

3 0

1 year ago

5 friends split 1/2 of a chocolate bar. How<br> much does each friend eat?<br> Draw a model.

Vinvika [58]

Answer:

1/10

Step-by-step explanation:

the friends eat 1/10 of the whole bar or 1/5 of half a bar

3 0

2 years ago

Solve each system of equations by graphing Y=3x+4 and y=-x-4

In-s [12.5K]

Y = 3x + 4
y = -x - 4

3x + 4 = -x - 4
3x + x = -4 - 4
4x = -8
x = -8/4
x = -2

y = 3x + 4
y = 3(-2) + 4
y = -6 + 4
y = -2

solution is (-2,-2) <==

6 0

3 years ago

a phone company offers two monthly plans. plan A costs 13 plus an additional 0.16 for each minute of calls. Plan B costs 24 plus

vladimir1956 [14]

Answer:

Let x represent number of calling minutes

Step-by-step explanation:

17 + .11x = 22 + .07x

.04x = 5

x = 5/.04 = 125 minutes, is the number of minutes the two plans cost the same

17 + .11*125 = $30.75 is the cost when the two plans cost the same

5 0

3 years ago