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MAXImum [283]
3 years ago
9

PLEASE HELP!!!!! The data set below shows the number of homework assignments required in math classes for a month:

Mathematics
2 answers:
NISA [10]3 years ago
8 0
There is one outlier that indicates an unusually small number of assignments required in that class
Vika [28.1K]3 years ago
4 0

Answer:

The correct option is 2.

Step-by-step explanation:

The given data set is

22, 23, 23, 21, 18, 4, 17, 15, 23, 20, 24, 15, 25, 16

Arrange the data is ascending order.

4, 15, 15, 16, 17, 18, 20, 21, 22, 23, 23, 23, 24, 25

Divide the data in 4 equal parts.

(4, 15, 15), 16, (17, 18, 20), (21, 22, 23), 23, (23, 24, 25)

Now, we can say that

Q_1=16

Q_3=23

The interquartile range of the data set is

IQR=Q_3-Q_1=23-16=7

If the data lie in the interval [Q_1-1.5(IQR),Q_3+1.5(IQR)], then the data set has not outliers.

[Q_1-1.5(IQR),Q_3+1.5(IQR)]=[16-1.5(7),23+1.5(7)]\Rightarrow [5.5,33.5]

All the data lie in the interval [5.5,33.5] except 4. So, 4 is an outlier of the given data.

There is one outlier that indicates an unusually small number of assignments required in that class. Therefore the correct option is 2.

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Which of the following graphs could be the graph of the function f(x)=-0.08x(x^2-11x+18)?
MariettaO [177]

Answer:

option C

Step-by-step explanation:

f(x)=-0.08x(x^2-11x+18)

Factor the parenthesis and find out the x intercepts

(x^2-11x+18)

We find out two factors whose product is 18 and sum is -11

-9  and -2 gives us product 18

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(x^2-11x+18) =(x-9)(x-2)

f(x)=-0.08x(x^2-11x+18)

f(x)= -0.08x(x-9)(x-2)

set f(x) =0  and solve for x

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-0.08x =0, so x=0

x-9 = 0 , so x=9

x-2 =0 , so x=2

x intercepts are (0,0) (2,0)  and (9,0)

x intercepts are not repeating

so the graph crosses x -axis at x=0, 2,9

option C is correct

The graph is attached below4


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