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3 years ago

Write 83 as a sum of tens and ones

Mathematics

2 answers:

kvv77 [185]3 years ago

7 0

8 tens ans 3 ones.....theres your answer

MrMuchimi3 years ago

3 0

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Solve question ( x + 4 ) ( x+2 )

nexus9112 [7]

X^2+6x+8 if you multiply

8 0

3 years ago

Read 2 more answers

If 5/2 kg of carrots cost $3,how much will 3/2 kg cost?

VashaNatasha [74]

Answer:

first you find out how much will 1/2 kg of carrot cost, that way you can multiply it by 3 to get what 3/2 cost.

So, 3÷ 5 = 0.6 per 1/2 kg. Then 0.6 × 3 = 1.8 dollars for 3/2 kg

7 0

3 years ago

Write a polynomial that has a GCF of 7m and another with a GCF of 2ab squared.

SVEN [57.7K]

The polynomial that has a GCF of 7m is 14mn - 21m + 49m²n + 7mn²

The polynomial that has a GCF of 2ab² is 6a²b² - 8ab³ + 4a³b² + 2a³b³

<h3>Writing Polynomials </h3>

From the question, we are to write a polynomial that has a GCF of 7m

That is,

We are to write a polynomial that has a greatest common factor of 7m

<em>Writing the polynomial</em>

14mn - 21m + 49m²n + 7mn²

The polynomial above has a greatest common factor of 7m. That is, 7m is the greatest factor that can divide each of the terms

We are to write a polynomial with a GCF of 2ab²

<em />

<em>Writing the polynomial</em>

6a²b² - 8ab³ + 4a³b² + 2a³b³

The polynomial above has a greatest common factor of 2ab². That is, 2ab² is the greatest factor that can divide each of the terms

Hence,

The polynomial that has a GCF of 7m is 14mn - 21m + 49m²n + 7mn²

The polynomial that has a GCF of 2ab² is 6a²b² - 8ab³ + 4a³b² + 2a³b³

Learn more on Writing polynomials here: brainly.com/question/4525973

#SPJ1

7 0

1 year ago

Simplify to create an equivalent expression. 2(3r+7)−(2+r)

tamaranim1 [39]

2(3r+7)−(2+r)

Use distributive property:

6r + 14 - 2 - r

Simplify by combining like terms:

5r +12

7 0

3 years ago

The volume of a cone of radius r and height h is given by V=πr²h³. If the radius and the height both increase at a constant rate

Aloiza [94]

Answer:

The volume of cone is increasing at a rate 1808.64 cubic cm per second.

Step-by-step explanation:

We are given the following in the question:

$\dfrac{dr}{dt} = 12\text{ cm per sec}\\\\\dfrac{dh}{dt} = 12\text{ cm per sec}$

Volume of cone =

$V = \dfrac{1}{3}\pi r^2 h$

where r is the radius and h is the height of the cone.

Instant height = 9 cm

Instant radius = 6 cm

Rate of change of volume =

$\dfrac{dV}{dt} = \dfrac{d}{dt}(\dfrac{1}{3}\pi r^2 h)\\\\\dfrac{dV}{dt} = \dfrac{\pi}{3}(2r\dfrac{dr}{dt}h + r^2\dfrac{dh}{dt})$

Putting values, we get,

$\dfrac{dV}{dt} = \dfrac{\pi}{3}(2(6)(12)(9) + (6)^2(12))\\\\\dfrac{dV}{dt} =1808.64\text{ cubic cm per second}$

Thus, the volume of cone is increasing at a rate 1808.64 cubic cm per second.

5 0

3 years ago