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schepotkina [342]
3 years ago
10

a 46 inch piece of Steel is cut into three pieces so that the second piece is twice as long as the first piece and third piece i

s one in more than six times the length of the first piece find the length of the pieces
Mathematics
1 answer:
Natasha2012 [34]3 years ago
4 0
X,2x,6x+1=46
(46-1)/5
x=5
5,10,31
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Rzqust [24]

Answer:

6

Step-by-step explanation:

3 0
3 years ago
Please help me answer this!!!
iragen [17]
It is D if u did the math right
8 0
2 years ago
The graph of f(x) = x^2 has been shifted into the form f(x) = (x − h)^2 + k
stepan [7]
\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\
% left side templates
\begin{array}{llll}
f(x)=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
y=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
f(x)=&{{  A}}\sqrt{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
f(x)=&{{  A}}(\mathbb{R})^{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
f(x)=&{{  A}} sin\left({{ B }}x+{{  C}}  \right)+{{  D}}
\end{array}\\\\
--------------------\\\\

\bf \bullet \textit{ stretches or shrinks horizontally by  } {{  A}}\cdot {{  B}}\\\\
\bullet \textit{ flips it upside-down if }{{  A}}\textit{ is negative}\\
\left. \qquad   \right.  \textit{reflection over the x-axis}
\\\\
\bullet \textit{ flips it sideways if }{{  B}}\textit{ is negative}\\
\left. \qquad   \right.  \textit{reflection over the y-axis}

\bf \bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\
\left. \qquad  \right. if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\\\
\left. \qquad  \right.  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\\\
\bullet \textit{ vertical shift by }{{  D}}\\
\left. \qquad  \right. if\ {{  D}}\textit{ is negative, downwards}\\\\
\left. \qquad  \right. if\ {{  D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{  B}}}

with that template in mind, let's see, it went to the right 2 units, and then up 3 units.

that simply means, C = -2, D = 3.
8 0
2 years ago
I don’t understand how to do this
schepotkina [342]

Answer:

The solution is x =0.

Step-by-step explanation:

The equation

\bold{(1).}\: sin(\dfrac{3\pi }{2} +x)+sin(\dfrac{3\pi }{2} +x) =-2

can be rewritten as

2* sin(\dfrac{3\pi }{2} +2) =-2

and can be further simplified to

sin(\dfrac{3\pi }{2}+x ) =-1.

Now, taking the inverse sine of both sides we get:

sin^{-1}(sin(\dfrac{3\pi }{2} +x) =sin^{-1}(-1)

\bold{(2).}\:  \dfrac{3\pi }{2} +2 =sin^{-1}(-1)

The value of the right side on the interval [0,2\pi) is

sin^{-1}(-1) = \dfrac{3\pi}{2} \: \:( \text{or }270^o) ,

which makes the equation (2)

\dfrac{3\pi }{2}+x  =\dfrac{3\pi}{2}

solving for x gives

\boxed{x = 0}

which is our solution.

4 0
3 years ago
For each graph below, state whether it represents a function.<br>​
UkoKoshka [18]
Graph1-Yes
Graph2-yes
Graph 3- NO
Graph4-yes
Graph5-No
Graph6/No
5 0
2 years ago
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