Assuming those are the legs of the triangle and that you need to find the hypotenuse... I would use the formula: a^2+b^2=c^2
It doesn't matter what a and b are, just fill it in.
25^2+35^2=c^2
625+1225=c^2
1850=c^2
Take the square root of 1850, it isn't a perfect square so I got: 43.01.
If you want, just round it to 43, idc.
So, if I were to check my work, I would need to remember that the hypotenuse is the longest side.
Since 43 is the hypotenuse, it is the longest side.
(6/2) - 4 would be your answer
We have to add the amounts:
4(2x+3y) + 3(5x+4)
First, though, we have to distribute:
4*2x + 4*3y + 3*5x + 3*4
8x + 12y + 15x + 12
Now we just need to simplify:
23x + 12y + 12
The students planted 23x + 12y + 12 trees total.
The original number is 72
(18+x)/6 = 1+14
1/6x + 3 = 1 + 14 (Distribute)
1/6x + 3 = (1+14) (Combine Like Terms)
1/6x + 3 = 15
- 3 = -3 (Subtract 3 From Both Sides)
1/6x = 12
(1/6x)*6 = 12 * 6 (Multiply Both Sides By 6)
x = 72
Answer:
there are only 4 whole numbers whose squares and cubes have the same number of digits.
Explanations:
let 0, 1, 2 and 4∈W (where W is a whole number), then
, 
,
, 
,
, 
,
, 
.
You can see from the above that only four whole numbers are there whose squares and cubes have the same number of digits
