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laila [671]
3 years ago
6

The surface area of a die is 600 mm squared. What is the volume of the die?

Mathematics
1 answer:
Alborosie3 years ago
5 0
A die has six sides so each one has an area of 100mm
Since it is a square shape we can take to square root to figure what the length width and height are equal to (its a cube so they're all the same)
√100=10
V=lwh so we do 10mm*10mm*10mm which is equal to 1000 mm^3
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Write the fraction 5/8 as a percent and as a decimal.
Sergio [31]

Answer:

<em>0.625</em>

<em>62.5%</em>

Step-by-step explanation:

5/8 is 0.625 as a decimal and

0.625*100 is 62.5 as a percent

7 0
3 years ago
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In a recent year, the ACT scores for the math portion of the test were normally distributed, with a mean of 21.1 and a standard
Natali5045456 [20]

Answer:

a) P(X

And we can find this probability using the normal standard table or excel:

P(z

b) P(19

And we can find this probability with this difference:

P(-0.396

And in order to find these probabilities we can use tables for the normal standard distribution, excel or a calculator.  

P(-0.396

c) P(X>26)=P(\frac{X-\mu}{\sigma}>\frac{26-\mu}{\sigma})=P(Z>\frac{26-21.1}{5.3})=P(z>0.925)

And we can find this probability using the complement rule and the normal standard table or excel:

P(z>0.925)=1- P(Z

d) We can consider unusual events values above or below 2 deviations from the mean

Lower = \mu -2*\sigma = 21.1 -2*5.3 =10.5

A value below 10.5 can be consider as unusual

Upper = \mu +2*\sigma = 21.1 +2*5.3 =31.7

A value abovr 31.7 can be consider as unusual

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Part a

Let X the random variable that represent the scores of a population, and for this case we know the distribution for X is given by:

X \sim N(21.1,5.3)  

Where \mu=21.1 and \sigma=5.3

We are interested on this probability

P(X

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X

And we can find this probability using the normal standard table or excel:

P(z

Part b

P(19

And we can find this probability with this difference:

P(-0.396

And in order to find these probabilities we can use tables for the normal standard distribution, excel or a calculator.  

P(-0.396

Part c

P(X>26)=P(\frac{X-\mu}{\sigma}>\frac{26-\mu}{\sigma})=P(Z>\frac{26-21.1}{5.3})=P(z>0.925)

And we can find this probability using the complement rule and the normal standard table or excel:

P(z>0.925)=1- P(Z

Part d

We can consider unusual events values above or below 2 deviations from the mean

Lower = \mu -2*\sigma = 21.1 -2*5.3 =10.5

A value below 10.5 can be consider as unusual

Upper = \mu +2*\sigma = 21.1 +2*5.3 =31.7

A value abovr 31.7 can be consider as unusual

6 0
3 years ago
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schepotkina [342]
50 out of the 80 were adults if you have to round so it would be 5/8 then you just do 8×100 and then 5×180+70÷100 because you're want to do not do not do it
8 0
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Answer:

The answer should B, only one makes sense

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Please help , will mark brainliest.
bagirrra123 [75]

Answer: 30 ft

hope this helped :)

4 0
3 years ago
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