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ddd [48]
3 years ago
15

Please help?? Thank you if you help me

Mathematics
1 answer:
Luden [163]3 years ago
7 0
Y2-y1 over x2-x1 or you can go onto the calculator and push list and put  in the points and it will give you the answer of 68

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(a) The proportion of accidents that occur up to mile 1.2 of the path is the area under the density curve between 0 miles and 1.
inn [45]

Answer:

the area would be 0.4 or 40%

Step-by-step explanation:

The computation of the area is given below:

But before that the level of the density is

The density level is

=  1 ÷ (3 - 0)

= 1 ÷ 3

Area from 0 miles to 1.2 miles

= (1 ÷ 3) × (1.2 - 0)

= 0.4 or 40 %

Hence, the area would be 0.4 or 40%

the same is considered and relevant too

4 0
3 years ago
Simplify 38 over 49 what’s the anwswer
Katyanochek1 [597]

Answer: 38 over 49 can be written as 38/49. When divided, you will get 0.77551020408. It takes lots of regrouping, but it ends eventually.

If you are reducing it as a fraction, it is not possible because there is no other number to reduce it, so it will be in it's simplest form already.

8 0
3 years ago
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OLEASE DO THIS ITS EASY PKEAS EI NEED TO FINISH IT NOW PKEASE
KATRIN_1 [288]
For x y chart 19.36.2.27.13
8 0
3 years ago
What is the slope the line?
laila [671]

Answer:

the slope is 3/4x

Step-by-step explanation:

if you need it in slope intercept form too its y=3/4x-1

4 0
3 years ago
Last Sunday a certain store sold copies of 256 Newspaper A for $1.00 each and copies of Newspaper B for $1.25 each, and the stor
Marat540 [252]

Answer:

D. \frac{400p}{500-p}

Step-by-step explanation:

let's call A the number of copies sold of newspaper A and B the number of copies sold of newspaper B.

So, we can formulate the following equations from the sentence: a certain store sold copies of 256 Newspaper A for $1.00 each and copies of Newspaper B for $1.25 each as:

A + B = 256                               (1)

1A + 1.25 B = Total Revenue    (2)

Then, r and p are equal to:

r=\frac{A}{Total Revenue}*100=\frac{100A}{A+1.25B}     (3)

p=\frac{A}{256} *100=\frac{100A}{256}                            (4)

Isolating A from (4) and B from (1), we get:

A=\frac{256p}{100} =2.56p                (5)

B=256-A=256-2.56p                         (6)

Finally, replacing (5) and (6) in (3), we get:

r=\frac{100A}{A+1.25B}=\frac{100(2.56p)}{2.56p+1.25(256-2.56p)}\\\\r=\frac{256p}{2.56p+320-3.2p}=\frac{256p}{320-0.64p}\\\\r=\frac{256p/0.64}{(320-0.64p)/0.64}=\frac{400p}{500-p}

7 0
4 years ago
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