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lesya [120]
2 years ago
13

I need the answer from the question

Mathematics
1 answer:
alexdok [17]2 years ago
3 0

Answer:

B

Step-by-step explanation:

Hope this helps :)

Have a great day!

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if i have a 65.05% (D) in a class and i get a 100% on an assignment that worth 10% of my grade, what would my grade be
lord [1]
I’m pretty sure you would have a 72% which would be a low C but maybe still passing. My schools passing grade is 70%. You would have to see what a passing grade is in your school.
4 0
2 years ago
When x = 4, the value of 2x0 + x! is
Romashka [77]
4!= 4*3*2*1

Therefore,

2x0+x!= 0+x! = 0+4!


4*3*2*1 = 24  (#1)
4 0
3 years ago
Read 2 more answers
What is x/5+7=16 gonna be?
Margarita [4]

x=45

Step-by-step explanation:

x/5+7-7=16-7

5/1×x/5=9×5/1

x=45

6 0
3 years ago
What the recursive formula for the sequence
klemol [59]

\bf n^{th}\textit{ term of an arithmetic sequence} \\\\ a_n=a_1+(n-1)d\qquad \begin{cases} n=n^{th}\ term\\ a_1=\textit{first term's value}\\ d=\textit{common difference} \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ a_n=2-5(n-1)\implies a_n=\stackrel{\stackrel{a_1}{\downarrow }}{2}+(n-1)(\stackrel{\stackrel{d}{\downarrow }}{-5})


so, we know the first term is 2, whilst the common difference is -5, therefore, that means, to get the next term, we subtract 5, or we "add -5" to the current term.

\bf \begin{cases} a_1=2\\ a_n=a_{n-1}-5 \end{cases}


just a quick note on notation:

\bf \stackrel{\stackrel{\textit{current term}}{\downarrow }}{a_n}\qquad \qquad \stackrel{\stackrel{\textit{the term before it}}{\downarrow }}{a_{n-1}} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{current term}}{a_5}\qquad \quad \stackrel{\textit{term before it}}{a_{5-1}\implies a_4}~\hspace{5em}\stackrel{\textit{current term}}{a_{12}}\qquad \quad \stackrel{\textit{term before it}}{a_{12-1}\implies a_{11}}

8 0
3 years ago
Add using Scratch Addition. 45 + 58 + 29 + 59 + 67 + 37 + 55 + 79 + 87 3​
soldier1979 [14.2K]
92836393749484037403
7 0
3 years ago
Read 2 more answers
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