State a counterexample to the conjecture below if a number is divisible by 6 and 2 then there’s is divisible by 12

Mathematics

2 answers:

Lisa [10]2 years ago

7 0

If there's is not divisible by 12 then the number is not divisible by 6 and 2. Hope this helps.

siniylev [52]2 years ago

4 0

Any number that is divisible by 6 is already divisible by 2, but is not necessarily divisible by 12.

Counterexamples include: 6, 18, 30, 42, 54, and so on. You can find more by multiplying 6 by any odd number. However, multiplying 6 by an even number provides another "2" that would make it divisible by 12.

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A cook has 11 7/8 cups of flour. He uses 2/3 of his flour on Saturday morning. Estimate how many cups he used. Show how you esti

ziro4ka [17]

Answer:

11 (if you wanna know how many cups [which i mean by 2/3] it is 1)

Step-by-step explanation:

Well, to start, a cook has 11 7/8 cups of flour, right? Well, if you subtract 11 7/8 by 2/3 you get 11 5/24. As an estimate, you would get just plain 11 because there is three numbers when you estimate, 11, 11 1/2, or 12. 11 5/24 is more closer to 11 (because 1/2 would be 11 12/24, and 12 would be 11 13/24 or more until 12)

Hope it helped...

4 0

2 years ago

Read 2 more answers

What is a solution to the equation 3 / m + 3 - M / 3 - M equals m^2 + 9 / m^2-9?

Mnenie [13.5K]

Answer: Last option.

Step-by-step explanation:

Given the equation:

$\frac{3}{m+3}-\frac{m}{3-m}=\frac{m^2+9}{m^2-9}$

Follow these steps to solve it:

- Subtract the fractions on the left side of the equation:

$\frac{3(3-m)-m(m+3)}{(m+3)(3-m)}=\frac{m^2+9}{m^2-9}\\\\\frac{9-3m-m^2-3m}{(m+3)(3-m)}=\frac{m^2+9}{m^2-9}\\\\\frac{-m^2-6m+9}{(m+3)(3-m)}=\frac{m^2+9}{m^2-9}$