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3 years ago

Find the range of the following set of data. 130, 110, 121, 141, 137, 136, 103, 144

Mathematics

2 answers:

True [87]3 years ago

8 0

Answer:

Step-by-step explanation:

Given : 130, 110, 121, 141, 137, 136, 103, 144

Range = Highest Value - Lowest Value

In this case, the highest value is 144 and the lowest value is 103

hence Range = 144 - 103 = 41

Galina-37 [17]3 years ago

8 0

Answer:

41.

Step-by-step explanation:

The range = highest - lowest value

= 144 - 103

= 41.

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Which of the following shows a number in fraction form?

Galina-37 [17]

2/1 that the answer to your question

3 0

3 years ago

After taxes, Olive brings home $2,800 per month. She has decided that she would like to set aside 15% of her income for savings.

podryga [215]

Answer:

Olive will save $420 each month.

Step-by-step explanation:

This question can be solved using a rule of three.

Olive earns $2,800 a month. $2,800 is 100% = 1 of her earnings. She wants to save x, which is 15% = 0.15 of her income. How much is x?

2800 - 1

x - 0.15x

x = 2800*0.15 = $420

Olive will save $420 each month.

5 0

3 years ago

What is 1,339,032 ÷ 19 and the remainder?

Varvara68 [4.7K]

70475.36 is the correct answer to your question

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3 years ago

Xiao's teacher asked him to rewrite the sum 60+90 as the product of the GCF of the two numbers and a sum. Xiao's wrote 3(20 + 30

Kobotan [32]

His answer works ... it gives 150, which is the same as (60 + 90) ... but he didn't deliver exactly what the problem asked for.

It asked for the <u>GCF</u> to be outside the parentheses, and he put '3' there.

'3' is certainly one common factor of 60 and 90, but it's far from being the
greatest one.

The GCF of 60 and 90 is actually 30 . So the absolutely positively technically correct response to the instructions in the problem would be 30(2 + 3).

8 0

3 years ago

The weight of a product is normally distributed with a mean of four ounces and a variance of .25 squared ounces. What is the pro

ololo11 [35]

Answer:

$P(X>3.75)=P(\frac{X-\mu}{\sigma}>\frac{3.75-\mu}{\sigma})=P(Z>\frac{3.75-4}{0.5})=P(z>-0.5)$

And we can find this probability using the complement rule and we got:

$P(z>-0.5)=1-P(z$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

Let X the random variable that represent the weights of a population, and for this case we know the distribution for X is given by:

$X \sim N(4,\sqrt{0.25}=0.5)$