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s344n2d4d5 [400]
3 years ago
5

Given vectors u = (-3,2) and v = (4,-1), if vector w=2u -3v, what is ||w|| ?

Mathematics
1 answer:
Brums [2.3K]3 years ago
7 0
\bf \begin{cases}
u=\ \textless \ -3,2\ \textgreater \ \\
2u=2\ \textless \ -3,2\ \textgreater \ \\
\qquad \ \textless \ 2\cdot -3,2\cdot 2\ \textgreater \ \\
\qquad \boxed{\ \textless \ -6,4\ \textgreater \ }\\
----------\\
v=\ \textless \ 4,-1\ \textgreater \ \\
3v=3\ \textless \ 4,-1\ \textgreater \ \\
\qquad \ \textless \ 3\cdot 4,3\cdot -1\ \textgreater \ \\
\qquad \boxed{\ \textless \ 12,-3\ \textgreater \ }
\end{cases}\qquad
\begin{array}{llll}
w=2u-3v\\\\
w=\ \textless \ -6,4\ \textgreater \ -\ \textless \ 12,-3\ \textgreater \ \\\\
w=\ \textless \ -6-12,4-(-3)\ \textgreater \ \\\\
w=\ \textless \ -18,4+3\ \textgreater \ \\\\
\boxed{w=\ \textless \ -18,7\ \textgreater \ }
\end{array}
\\\\\\
||w||\implies \sqrt{a^2+b^2}\implies ||w||=\sqrt{(-18)^2+(7)^2}\implies ||w||=373
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3 years ago
Can someone help me please and thank you
s344n2d4d5 [400]
Okay.
Well, first of all you need to know what an x-intercept is. 
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Out of that table you have two that apply to (#, 0)
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the question is asking for a positive x-intercept. I'm guessing you know the difference. between negative and positive. but just in case, I'll use the number 5. As a positive: 5 As a negative: -5
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I hope this helped! :)
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3 years ago
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igor_vitrenko [27]

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7 0
3 years ago
Read 2 more answers
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MissTica

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BaLLatris [955]

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2 years ago
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