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stepladder [879]
3 years ago
12

The circumference of the great wheel was twelve thousand and forty-one thousand inches. The cricumference of the lesser wheel wa

s only one thousand twenty-one and two hundred-thousand inches. How much lager was the great wheel?
Mathematics
1 answer:
Korvikt [17]3 years ago
5 0

Answer:

The larger wheel is 10979.04098 more than the smaller wheel.

Step-by-step explanation:

Given that,

The circumference of the great wheel was twelve thousand and forty-one thousandth inches.

C = 12000.041 inches

The circumference of the lesser wheel was only one thousand twenty-one and two hundred-thousand inches.

C' = 1021.00002 inches

We need to find how much larger was the great wheel. To find it, take the difference of C and C'.

C-C' = 12000.041 inches - 1021.00002 inches

= 10979.04098 inches

Hence, the larger wheel is 10979.04098 more than the smaller wheel.

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Step-by-step explanation:

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If H is in the interior of ∠EFG, m∠EFH = 75°, and m∠HFG = (10x)°, and m∠EFG = (20x − 5)°, then x = ? and m∠HFG = ?
Diano4ka-milaya [45]

Answer:

x=8

\m\angle HFG= 80^\circ

Step-by-step explanation:

Given that:

Point H is interior of \angle EFG.

m\angle EFH = 75^\circ\\m\angle HFG = (10x)^\circ\\m\angle EFG = (20x-5)^\circ

To find:

x = ?\\m\angle HFG = ?

Solution:

First of all, let us represent the given values in the form of a diagram.

Kindly refer to the attached image for the given points and values of angles.

We can clearly see that:

m\angle EFG = m\angle EFH + m\angle HFG

Putting all the values given in above equation, we get:

(20x-5)^\circ = 75^\circ + 10x^\circ\\\Rightarrow 20x-10x=75+5\\\Rightarrow 10x =80\\\Rightarrow \bold{x =8}

m\angle HFG =10x^\circ\\\Rightarrow m\angle HFG =10\times 8^\circ\\\Rightarrow m\angle HFG = \bold{80^\circ}

8 0
3 years ago
Simplify the expression: 4(9c − 7)
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Step-by-step explanation:

4(9c − 7)

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36c - 28

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3 years ago
Pls, help me with this 1 problem.
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Answer:

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Step-by-step explanation:

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200 exponent 2 = 40,000
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