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WARRIOR [948]
3 years ago
11

What is 35\42 in simplest form

Mathematics
1 answer:
Ostrovityanka [42]3 years ago
4 0
To put a fraction into simplest form, you need to divide both the numerator and the denominator by the GCF of both of these numbers.

35 and 42 have a GCF of 7.  

So, if we divide
35/7=5
42/7=6

Therefore, 35/42 in simplest form is 5/6
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On Monday you read 3 pages.
spin [16.1K]

Answer:

27 pages

Step-by-step explanation:

Since you read 3 pages on Monday and you read 3 times that number on Tuesday, the equation should be 3*3 to equal 9. Then, since you read 9 pages on Tuesday and 3 times that number on Wednesday, the equation should be 9*3 to equal 27 pages. So, on Wednesday, you read 27 pages in total.

8 0
3 years ago
Read 2 more answers
In Triangle XYZ, measure of angle X = 49° , XY = 18°, and
marissa [1.9K]

Answer:

There are two choices for angle Y: Y \approx 54.987^{\circ} for XZ \approx 15.193, Y \approx 27.008^{\circ} for XZ \approx 8.424.

Step-by-step explanation:

There are mistakes in the statement, correct form is now described:

<em>In triangle XYZ, measure of angle X = 49°, XY = 18 and YZ = 14. Find the measure of angle Y:</em>

The line segment XY is opposite to angle Z and the line segment YZ is opposite to angle X. We can determine the length of the line segment XZ by the Law of Cosine:

YZ^{2} = XZ^{2} + XY^{2} -2\cdot XY\cdot XZ \cdot \cos X (1)

If we know that X = 49^{\circ}, XY = 18 and YZ = 14, then we have the following second order polynomial:

14^{2} = XZ^{2} + 18^{2} - 2\cdot (18)\cdot XZ\cdot \cos 49^{\circ}

XZ^{2}-23.618\cdot XZ +128 = 0 (2)

By the Quadratic Formula we have the following result:

XZ \approx 15.193\,\lor\,XZ \approx 8.424

There are two possible triangles, we can determine the value of angle Y for each by the Law of Cosine again:

XZ^{2} = XY^{2} + YZ^{2} - 2\cdot XY \cdot YZ \cdot \cos Y

\cos Y = \frac{XY^{2}+YZ^{2}-XZ^{2}}{2\cdot XY\cdot YZ}

Y = \cos ^{-1}\left(\frac{XY^{2}+YZ^{2}-XZ^{2}}{2\cdot XY\cdot YZ} \right)

1) XZ \approx 15.193

Y = \cos^{-1}\left[\frac{18^{2}+14^{2}-15.193^{2}}{2\cdot (18)\cdot (14)} \right]

Y \approx 54.987^{\circ}

2) XZ \approx 8.424

Y = \cos^{-1}\left[\frac{18^{2}+14^{2}-8.424^{2}}{2\cdot (18)\cdot (14)} \right]

Y \approx 27.008^{\circ}

There are two choices for angle Y: Y \approx 54.987^{\circ} for XZ \approx 15.193, Y \approx 27.008^{\circ} for XZ \approx 8.424.

6 0
3 years ago
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maksim [4K]
Lo siento, no hablo español
8 0
3 years ago
Okay Ju|ian Foley simplifies this polynomial and then write it in standard form if Ju|ian wrote it the last term
Fudgin [204]

Answer:

the second choice

Step-by-step explanation:

8 0
3 years ago
Compare 2 x 10^4 and 8 x 10^3
agasfer [191]
2* 10^4 would be bigger than 8* 10^3.

10^4 = 10000*2=20000
10^3 = 1000*8=8000
8 0
3 years ago
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