Which inequality is equivalent to I x-4 I <9

Mathematics

1 answer:

Leni [432]1 year ago

4 0

(B) –9 < x – 4 < 9 inequality is equivalent to Ix-4I <9.

<h3>What is inequality?</h3>

Inequality is a statement of an order relationship between two numbers or algebraic expressions (greater than, greater than, or equal to, less than, or less than or equal to).
Inequality is defined as a difference in size, amount, quality, social position, or another factor.
Inequality occurs when you have ten of something and someone else has none.
(mathematics) A statement stating that one quantity is less than (greater than) another.

So, Ix-4I <9:

|x-4|<9 ⇒ -9 < x-4 < 9
-5 < x < 13

Therefore, (B) –9 < x – 4 < 9 inequality is equivalent.

Know more about inequality here:

brainly.com/question/11613554

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The complete question is given below:

Which inequality is equivalent to I x-4 I <9?

A –9 > x – 4 < 9

B –9 < x – 4 < 9

C x – 4 < –9 or x – 4 < 9

D x – 4 > –9 or x – 4 < 9

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Can someone answer these questions ? thank you

Naya [18.7K]

Answer:

Step-by-step explanation:

12a)To rationalize the denominator, multiply the denominator and numerator by √5.

$\frac{15}{\sqrt{5}}=\frac{15*\sqrt{5}}{\sqrt{5}*\sqrt{5}}\\\\=\frac{15\sqrt{5}}{5}\\\\=3\sqrt{5}$

b) (a+b)² = a² + 2ab + b²

(1 +√3)² = 1² + 2*1*√3 + (√3)²

= 1 + 2√3 + 3

= 4 + 2√3

a = 4 ; b =2

13) (a + b)(a - b) = a² - b²

$\frac{(6-\sqrt{5})(6+\sqrt{5})}{\sqrt{31}}=\frac{6^{2}-(\sqrt{5})^{2}}{\sqrt{31}}\\\\ =\frac{36-5}{\sqrt{31}}\\\\=\frac{31}{\sqrt{31}}\\\\=\frac{31*\sqrt{31}}{\sqrt{31}*\sqrt{31}}\\\\=\frac{31\sqrt{31}}{31}\\\\=\sqrt{31}$