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svet-max [94.6K]
3 years ago
6

Estimate the quotient 19 4/5 • 4 5/8

Mathematics
1 answer:
Allushta [10]3 years ago
7 0

Answer:

-0.1692

Step-by-step explanation:

use your cakculator

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A number cube is rolled 450 times. The number 3 comes up 67 times. What is the theoretical probability of rolling a three,
love history [14]
The answer to this is 67 / 450

We know that:
Experimental probability = number of positive results / number of experiments

So the Experimental probability = 67 / 450
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3 years ago
Please help me with this
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Answer:

11 cm

Step-by-step explanation:

1m = 100cm

By examining the graph carefully, we can see that the record in 1985 is 2.4 m. In 1970 it was slightly under 2.3 m. For it to be 15cm it would have to be 2.25m. For it to be 9 cm it would the record would have been above 2.3m.

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Two cars leave town at the same time and travel in opposite directions. The average rate of speed of one car is 15 miles per hou
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65 mph that would be the answer

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3 years ago
This due in 20 min please help me i will give brainliest
Vlad [161]

Answer:

1. 26.3 hrs

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Step-by-step explanation:

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3 years ago
Hyperbola Question:
AveGali [126]

Answer:

\dfrac{x^{2}}{1210000 } - \dfrac{y^{2}}{5759600} = 1

Step-by-step explanation:

A hyperbola is a curve for which the difference of the distances |d₂ - d₁| of any point P from the foci is constant.

The definition leads to the equation

\dfrac{x^{2}}{a^{2}} - \dfrac{y^{2}}{b^{2}} = 1

1. Calculate the value of a²

Assume the neighbours are at the foci A and B.

The explosion is farther from B than from A, so it occurred on the right branch of the hyperbola.

Then AB = 1 mi = 5280 ft

and the distance from the focus to the y-axis is

c = 2640

The vertices are (±a,0).

The speed of sound is 1100 ft/s, so B is 2200 ft further from the explosion.  

The distance from A to the vertex V₁ is c - a. Then

AB = 2200 + 2(c - a) = 2200 -2(2640 - 2a) = 2200 +5280- 2a = 5280

2a = 2200

a = 1100

a² = 1 210 000

2. Calculate the value of b²

\begin{array}{rcl}a^{2} + b^{2} & = & c^{2}\\1100^{2} + b^{2} & = & 2640^{2}\\b^{2} & = & 2640^{2} - 1100^{2}\\& = & 6969600 - 1210000\\& = & \mathbf{5759600}\\\end{array}

3. Write the equation for the hyperbola

\mathbf{\dfrac{x^{2}}{1210000 } - \dfrac{y^{2}}{5759600}} = \mathbf{1}

5 0
4 years ago
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