Answer:
D. Minimum at (3, 7)
Step-by-step explanation:
We can add and subtract the square of half the x-coefficient:
y = x^2 -6x +(-6/2)^2 +16 -(-6/2)^2
y = (x -3)^2 +7 . . . . . simplify to vertex form
Comparing this to the vertex for for vertex (h, k) ...
y = (x -h)^2 +k
We find the vertex to be ...
(3, 7) . . . . vertex
The coefficient of x^2 is positive (+1), so the parabola opens upward and the vertex is a minimum.
Answer:
Please see the attached images for explanation:
Step-by-step explanation:
Please let me know if you have any questions :)
Answer:
Step-by-step explanation:
Looking at y=-%282%2F3%29x%2B3 we can see that the equation is in slope-intercept form y=mx%2Bb where the slope is m=-2%2F3 and the y-intercept is b=3
Since b=3 this tells us that the y-intercept is .Remember the y-intercept is the point where the graph intersects with the y-axis
So we have one point
Now since the slope is comprised of the "rise" over the "run" this means
slope=rise%2Frun
Also, because the slope is -2%2F3, this means:
rise%2Frun=-2%2F3
which shows us that the rise is -2 and the run is 3. This means that to go from point to point, we can go down 2 and over 3
So starting at , go down 2 units
and to the right 3 units to get to the next point
Now draw a line through these points to graph y=-%282%2F3%29x%2B3
So this is the graph of y=-%282%2F3%29x%2B3 through the points and
Answer:
B, C, A, B
Step-by-step explanation:
