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Eddi Din [679]
2 years ago
8

What is the surface area of the square pyramid represented by

Mathematics
2 answers:
emmasim [6.3K]2 years ago
8 0
175m^2 because just took the test
Lostsunrise [7]2 years ago
7 0

Answer:

Answer: 175 cm²

From the given picture the surface area of square pyramid = Area of square+Area of 4 triangles.

Area of square = side^2=7^2=49 cm^2 By the way "^" means exponent sorry for the late reply

For triangles, base of triangle b=7 cm

Height of triangle= 9 cm

Area of square pyramid =Area of square+Area of 4 triangles.

Step-by-step explanation:

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Calculate the area of triangle ABC with altitude BD, given A (−6, 0), B (0, 0), C (0, 6), and D (−3, 3).
nata0808 [166]

Answer:

  • 18 unit²

Step-by-step explanation:

If BD is altitude then AC is the base.

<u>The length of AC is:</u>

  • AC = \sqrt{6^2+6^2} = 6\sqrt{2}

<u>The length of BD is:</u>

  • BD = \sqrt{3^2 + 3^2} = 3\sqrt{2}

<u>The area is:</u>

  • A = 1/2bh
  • A = 1/2 * 6\sqrt{2} *3\sqrt{2} = 18 unit²
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Express the integral as a limit of Riemann sums. Do not evaluate the limit. (Use the right endpoints of each subinterval as your
Veronika [31]

The expression of integral as a limit of Riemann sums of given integral \int\limits^5_b {1} \, x/(2+x^{3}) dxis 4 \lim_{n \to \infty}∑n(n+4i)/2n^{3}+(n+4i)^{3} from i=1 to i=n.

Given an integral \int\limits^5_b {1} \, x/(2+x^{3}) dx.

We are required to express the integral as a limit of Riemann sums.

An integral basically assigns numbers to functions in a way that describes displacement, area, volume, and other concepts that arise by combining infinite data.

A Riemann sum is basically a certain kind of approximation of an integral by a finite sum.

Using Riemann sums, we have :

\int\limits^b_a {f(x)} \, dx=\lim_{n \to \infty}∑f(a+iΔx)Δx ,here Δx=(b-a)/n

\int\limits^5_1 {x/(2+x^{3}) } \, dx=f(x)=x/2+x^{3}

⇒Δx=(5-1)/n=4/n

f(a+iΔx)=f(1+4i/n)

f(1+4i/n)=[n^{2}(n+4i)]/2n^{3}+(n+4i)^{3}

\lim_{n \to \infty}∑f(a+iΔx)Δx=

\lim_{n \to \infty}∑n^{2}(n+4i)/2n^{3}+(n+4i)^{3}4/n

=4\lim_{n \to \infty}∑n(n+4i)/2n^{3}+(n+4i)^{3}

Hence the expression of integral as a limit of Riemann sums of given integral \int\limits^5_b {1} \, x/(2+x^{3}) dxis 4 \lim_{n \to \infty}∑n(n+4i)/2n^{3}+(n+4i)^{3} from i=1 to i=n.

Learn more about integral at brainly.com/question/27419605

#SPJ4

5 0
2 years ago
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