First, subtract px2 from both sides.
Now you have:
x3 - px2 = (1 - p) x1
Next, divide both sides by (1 - p)
So now you have
x3 - px2/(1 - p) = x1
...as your final answer
*You can decide if you want to leave the parenthesis in your final answer, I left them there so it could be visible where I put them. :)
<span>1. Suppose that a family has an equally likely chance of having a cat or a dog. If they have two pets, they could have 1 dog and 1 cat, they could have 2 dogs, or they could have 2 cats.
What is the theoretical probability that the family has two dogs or two cats?
25% chance
</span><span>2. Describe how to use two coins to simulate which two pets the family has.
</span>
You could use the coins to simulate which pet the family has by flipping them and having head be dog and tails be cat (or vice-versa).
<span>3. Flip both coins 50 times and record your data in a table like the one below.
</span><span>Based on your data, what is the experimental probability that the family has two dogs or two cats?
</span>
Based on the results, I concluded that for Heads, Heads (which could be dogs or cats) there was a 24% chance and for Tails, Tails there was a 26% chance
<span>4. If the family has three pets, what is the theoretical probability that they have three dogs or three cats?
1/8 chance (accidentally messed up there) or 12.5%
</span><span>5. How could you change the simulation to generate data for three pets?
</span><span>
To flip 3 coins and add more spots on the chart.
I hope that this helps because it took a while to write out. If it does, please rate as Brainliest
</span>
2: 14+15d+9c
3: a.
ignore this I need 20 characters.:)))
.16666667 is your answer u have to round up the last number tho
Answer is A :) because it is rise over run
