To determine the mass of elemental iron in the elixir, we need to understand the given values given above. We are given the following:
Mass of ferrous sulfate = 220 mg
Volume of the elixir = 5 mL
Mass of elemental iron / mass of ferrous sulfate = 0.2 mg Fe / mg ferrous sulfate
Therefore, from the given values, we simply multiply the mass of the ferrous sulfate in the elixir and the equivalent mass of elemental iron per mass of ferrous sulfate. We do as follows:
Mass of Fe = 220 mg ferrous sulfate ( 0.2 mg Fe / mg ferrous sulfate )
Mass of Fe = 44 mg
The correct answer is C. Sugar dissolves in it
Hope this helps
-AaronWiseIsBae
Answer:
I think its E. iron and iron oxide have the same properties if it's not e its d for sure
Explanation:
iron + oxygen → iron oxide. 4 Fe + 3 O2 → 2 Fe2O.
Answer:red green and blue hope it helps!,!!!!!!!
Explanation:
It is bases on "Atomic number"
In short, Your Answer would be Option B
Hope this helps!