Sin0= y/r
X= -4 and r= 9 (radius is also the hypotenuse)
In quadrant II y is positive
X^2 +y^2 = r^2
-4^2 + y^2 = 9^2
16 + y^2 = 81
Y^2 = 81-16
Y^2 = 65
Y= sqrt65
Sin0= sqrt65/9
Just add two zeros to the front to make it kg .00123
Answer: 81pi square meters
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Work Shown
C = 18pi is the given circumference
d = diameter which is unknown
C = pi*d
18pi = pi*d
18 = d
d = 18
The diameter is 18 meters.
Half of this is the radius r = d/2 = 18/2 = 9
The radius is 9 meters
Use the value of r to find the area of the circle
A = pi*r^2
A = pi*9^2
A = pi*81
A = 81pi
The area of the circular cross section is 81pi square meters
Answer:
umm...1/12 of a chance
Step-by-step explanation:
Are you sure there isnt a graph that goes along with this?