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Lapatulllka [165]

4 years ago

7

How to get exact value of cos pi/2?

1 answer:

MrRa [10]4 years ago

4 0

Alternative form =6.28319

You might be interested in

What is the simplified form of the square root of 80?

djyliett [7]

$\sqrt{80} = \sqrt{2 * 2* 2* 2* 5} = \sqrt{2^{2}*2^{2}*5} = 2*2* \sqrt{5} = 4 \sqrt{5}$
Hope this helps.

3 0

4 years ago

BRAINLYYYY PLUS 100 PointsThe difference between two numbers is 84 and their sum is 278. What are the numbers? Hint( answer is x

den301095 [7]

Answer:

x = 181 and y = 97

Step-by-step explanation:

let called the first number is x

the second number would be called y

We are given that:

x + y = 278 (1)

x = y + 84 (2)

Let change x in (2) into (1):

y + 84 + y = 278

2y + 84 = 278

Subtract 84 from both side, we got:

2y + 84 - 84 = 278 - 84

2y + 0 = 194

Divide both side by 2, we got:

2y / 2 = 194 / 2

y = 97

Because y = 97 and x + y = 278 so x would equal:

x + 97 = 278

Subtract 97 from both side, we got:

x + 97 - 97 = 278 - 97

x + 0 = 181

x = 181 and y = 97

Hope this helped :3

4 0

3 years ago

Heidi solved the equation 3(x + 4) + 2 = 2 + 5(x – 4). Her steps are below: 3x + 12 + 2 = 2 + 5x – 20 3x + 14 = 5x – 18 14 = 2x

lyudmila [28]

Answer:

See explanation

Step-by-step explanation:

3(x + 4) + 2 = 2 + 5(x – 4)

Step 1: distributive property

3(x + 4) + 2 = 2 + 5(x – 4)

3x + 12 + 2 = 2 + 5x - 20

Step 2: collect like terms

3x + 12 + 2 = 2 + 5x - 20

3x + 14 = 5x - 18

Step 3: Addition property of equality

3x + 14 = 5x - 18

3x + 14 + 18 = 5x - 18 + 18

3x + 32 = 5x

Step 4: subtraction property of equality

3x + 32 - 3x = 5x - 3x

32 = 2x

Step 5: division property of equality

32 = 2x

32/2 = 2x/2

16 = x

x = 16

6 0

3 years ago

sesenic [268]

Ggggggghhggggggggggg

3 0

2 years ago

Read 2 more answers

In a triangle ABC, measure of angle B is 90 degrees. AB is 3x-2 units and BC is x+3. If the area of the triangle is 17 sq cm, fo

Scorpion4ik [409]

Answer:

$x=\frac{8}{3}\ cm$

Step-by-step explanation:

we know that

The area of the right triangle ABC is equal to

$A=\frac{1}{2}(AB)(BC)$

we have

$A=17\ cm^2$

$AB=(3x-2)\ cm$

$BC=(x+3)\ cm$

substitute the values

$17=\frac{1}{2}(3x-2)(x+3)$

$34=(3x-2)(x+3)$

$34=3x^2+9x-2x-6$

$3x^2+7x-6-34=0$

$3x^2+7x-40=0$

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$3x^2+7x-40=0$

so

$a=3\\b=7\\c=-40$

substitute in the formula

$x=\frac{-7(+/-)\sqrt{7^{2}-4(3)(-40)}} {2(3)}$

$x=\frac{-7(+/-)\sqrt{529}} {6}$

$x=\frac{-7(+/-)23} {6}$

$x=\frac{-7(+)23} {6}=\frac{16}{6}=\frac{8}{3}$

$x=\frac{-7(-)23} {6}=-5$

therefore

The solution is

$x=\frac{8}{3}\ cm$

6 0

3 years ago