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3 years ago

12

In a lottery game, a player picks six numbers from 1 to 20. If the player matches all six numbers, they win 30,000 dollars. Othe

rwise, they lose $1.
What is the expected value of this game?

1 answer:

natka813 [3]3 years ago

5 0

the expected value of the game is about -$0.90

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Answer:

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Step-by-step explanation:

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<u>Question # 1:</u>

Given that:

$\displaystyle \frac{p+10}{2} = 16\\\\Multiply\ both\ sides\ by \ 2]]\\ p+10 = 2 \times 16\\\\p+10 = 32\\\\Subtract \ 10\ to \ both \ sides\\\\p = 32-10\\\\p = 22$

<u>Question # 2:</u>

Given that:

$\displaystyle \frac{z+12}{2} = 10\\\\Multiply \ both \ sides \ by \ 2\\\\z+12 = 10 \times 2\\\\z+12 = 20\\\\Subtract \ 12\ to \ both \ sides\\\\z = 20-12\\\\z = 8\\\\\rule[224]{225}{2}$

Hope this helped!

<h3>~AH1807</h3>

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