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Ann [662]
3 years ago
13

Hi, please help me with this math problem, I need to submit rly quick, thx.

Mathematics
1 answer:
Artemon [7]3 years ago
6 0

Answer:

I think its B.

Step-by-step explanation:

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Carrie has a stamp collection she is very proud of. She buys a frame to display her favorite stamps. The frame is 6 inches wide,
olga55 [171]
The stamps should be .85 inches each
7 0
3 years ago
Marking Brainlist 7-9g+3g
coldgirl [10]

Answer:

7-6g

Then you do the 1 step equation.

Divide both sides by 6.

1.16=g

I'm not sure if it's right.

5 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B20%7D%20" id="TexFormula1" title=" \sqrt{20} " alt=" \sqrt{20} " align="absmiddle
tester [92]
The answer is going to be 2*sqrt(5). You have to split it into perfect squares for it to be simplified... so in this case, I had sqrt(4*5) because sqrt(4) can be simplified... so your answer would be sqrt(4)*sqrt(5) or 2sqrt(5)

8 0
4 years ago
1)
MrRissso [65]

Answer:

Step-by-step explanation:

The diagram of the triangles are shown in the attached photo.

1) Looking at ∆AOL, to determine AL, we would apply the sine rule

a/SinA = b/SinB = c/SinC

21/Sin25 = AL/Sin 105

21Sin105 = ALSin25

21 × 0.9659 = 0.4226AL

AL = 20.2839/0.4226

AL = 50

Looking at ∆KAL,

AL/Sin55 = KL/Sin100

50/0.8192 = KL/0.9848

50 × 0.9848 = KL × 0.8192

KL = 49.24/0.8192

KL = 60

AK/Sin25 = AL/Sin 55

AKSin55 = ALSin25

AK × 0.8192 = 0.4226 × 50

AK = 21.13/0.8192

AK = 25.8

2) looking at ∆AOC,

Sin 18 = AD/AC = 18/AC

AC = 18/Sin18 = 18/0.3090

AC = 58.25

Sin 85 = AD/AB = 18/AB

AB = 18/Sin85 = 18/0.9962

AB = 18.1

To determine BC, we would apply Sine rule.

BC/Sin77 = 58.25/Sin85

BCSin85 = 58.25Sin77

BC = 58.25Sin77/Sin85

BC = 58.25 × 0.9744/0.9962

BC = 56.98

7 0
3 years ago
Which equation below is a direct variation?
masya89 [10]
Direct variation is of the form y = kx where k is a constant

So its A
5 0
3 years ago
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