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Verizon [17]
3 years ago
13

marissa, john, and stephanie are working a 3- hour shift together. Marissa has an alarm on her phone that goes off every 12 minu

tes. John's phone alarm goes off every 30 minutes, and stephanie's phone alarm goes off every 45 minutes. If all their alarms went off at the same time 15 minutes into their shift, will they simultaneously go off again before their shift is over?
Mathematics
1 answer:
ioda3 years ago
6 0
3 hours =180mins

marrisa 15,28,42,56,68,80,92,104,116,128,140,152,164,176,188,
john 15,45,75,105,145,175,205
stephanie 15,60,105,150,195

no there alarm didnt go at the same tiem after the first time 
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4 0
4 years ago
Read 2 more answers
I think it’s b but I may be wrong
leonid [27]

Answer:

D, not B

Step-by-step explanation:

So using Pythagorean Theorem:

C^{2} =A^{2} +B^{2} \\x^{2} =144+265\\x^{2} =400\\x=20

Yep, It's not B, But D.

Hope this helps!

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6 0
3 years ago
Heather has her own bakery. She makes 4 pans of muffins each day. If her bakery is open 7 days a week, how many pans of muffins
OlgaM077 [116]

Answer:

28 pans of muffins per week

Step-by-step explanation:

To solve the above question, we know that:

1 day = 4 pans of muffins

7 days = x pans of muffins

Cross Multiply

1 day × x pans of muffins = 7 days × 4 pans of muffins

x = 28 pans of muffins

Since, 7 days = 1 week

Heather makes 28 pans of muffins per week

3 0
3 years ago
At 8am the temperature was-10 degrees farenheit. At 8 pm the temperature was -8. Which is warmer? Explain how you know.
Lana71 [14]
Would it be 8 am because sunlight might play a role???
8 0
3 years ago
find the value of "a" and "b" for which the limit exists both as x approaches 1 and as x approaches 2:
lbvjy [14]

Answer:

a = 4

b = -2

Step-by-step explanation:

If the given function is continuous at x = 1

\lim_{x \to 1^{-}} f(x)=(x+1)

                     =2

\lim_{x \to 1^{+}} f(x)=ax+b

                     =a+b

\lim_{x \to 1} f(x)=ax+b

                   =a+b

And for the continuity of the function at x = 1,

\lim_{x \to 1^{-}} f(x)=\lim_{x \to 1^{+}} f(x)=\lim_{x \to 1} f(x)

Therefore, (a + b) = 2 -------(1)

If the function 'f' is continuous at x = 2,

\lim_{x \to 2^{-}} f(x)=ax+b

                     =2a+b

\lim_{x \to 2^{+}} f(x)=3x

                     =6

\lim_{x \to 2} f(x)=3x

                   =6

Therefore, \lim_{x \to 2^{-}} f(x)=\lim_{x \to 2^{+}} f(x)=\lim_{x \to 2} f(x)

2a + b = 6 -----(2)

Subtract equation (1) from (2),

(2a + b) - (a + b) = 6 - 2

a = 4

From equation (1),

4 + b = 2

b = -2

3 0
3 years ago
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