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Natali [406]
3 years ago
13

About 70% of Earth’s surface is covered by water. If the diameter of Earth is about 12,750 km, find the area not covered by wate

r to the nearest 100,000 km2.
Mathematics
1 answer:
hichkok12 [17]3 years ago
4 0
Earth diameter = 12,750 km
Earth radius = 6,375 km
Sphere Surface Area     =    <span> 4 • <span>π <span>• r²
</span></span></span>Sphere Surface Area     =    4 * 3.141<span>59 * 6375^2
</span>Sphere Surface Area     =    4 * 3.14159 * <span> <span> <span> 40,640,625 </span> </span> </span>
<span> <span> <span> Earth's Entire </span></span></span><span>Surface Area     =    510,704,724 square kilometers
Surface NOT covered by water =  </span><span>510,704,724 * .3
</span>Surface NOT covered by water =  <span> <span> <span> 153,211,417</span></span></span><span> square kilometers</span>


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A light bulb consumes 960 watt-hours per day. How many watt-hours does it consume in
Kobotan [32]
960 watt-hpd 

5 x 60/6 = 50

50 x 960 = 48,000

Answer is: -->> 48,000



5 0
3 years ago
5 Ethan scored x points in a game. His younger sister scored 8 points when she
Nuetrik [128]

The remaining values will be<u> 19, 20, 21, 22 and 23</u>

<h3 /><h3>System of equations</h3>

Given the following parameters

Ethan's score = x points

His younger sister's score = 8 points

If their total score is y points, hence the  equation relating x and y is expressed as:

x + 8 = y

x = 8 - y

If x = 10

y = x + 8

y = 18

The ramining values will be<u> 19, 20, 21, 22 and 23</u>

Learn more on tables and values here: brainly.com/question/9265203

7 0
2 years ago
"How much do students pay, on average, for textbooks during the first semester in college? From a random sample of 400 students
dezoksy [38]

Answer: The margin of error = 3.71, confidence interval = (354.04, 361.46) and it means that mean cost is lies within the confidence interval.

Step-by-step explanation:

Since we have given that

Sample size = 400

Mean = $357.75

Standard deviation = $37.89

At 95% confidence level, z = 1.96

We first find the margin of error.

Margin of error is given by

z\times \dfrac{\sigma}{\sqrt{n}}\\\\=1.96\times \dfrac{37.89}{\sqrt{400}}\\\\=3.71

95% confidence interval would be

\bar{x}\pm \text{margin of error}\\\\=357.75\pm 3.71\\\\=(357.75-3.71,357.75+3.71)\\\\=(354.04,361.46)

Hence, the margin of error = 3.71, confidence interval = (354.04, 361.46) and it means that mean cost is lies within the confidence interval.

7 0
4 years ago
How to solve question 19<br> thanks
miskamm [114]
Let X be the random variable for the weight of any given can, and let \mu and \sigma be the mean and standard deviation, respectively, for the distribution of X.

You have

\begin{cases}\mathbb P(X377)=0.025\end{cases}

Recall that for any normal distribution, approximately 99.7% of it lies within three standard deviations of the mean, i.e. \mathbb P(\mu-3\sigma. This means 0.3% must lie outside this range, \mathbb P(X\mu+3\sigma)=0.003. Because the distribution is symmetric, it follows that \mathbb P(X.

Also recall that for any normal distribution, about 95% of it falls within two standard deviations of the mean, so \mathbb P(\mu-2\sigma, which means 5% falls outside, and by symmetry, \mathbb P(X>\mu+2\sigma)=0.025.

Together this means

\begin{cases}\mu-3\sigma=347\\\mu+2\sigma=377\end{cases}

Solving for the mean and standard deviation gives \mu=365 and \sigma=6.
6 0
4 years ago
Please help me with this question ASAP
valentina_108 [34]

Answer:

volume \:  =  \:  \frac{1}{2}  \times 6 \times 7 \times 16 \\  = 896

Hope it helps

5 0
3 years ago
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