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n200080 [17]
3 years ago
10

At the calendar shop, wall calendars cost $5 and desk calendars cost $1. Adriana spent $20 to buy 8 calendars. How many of each

type of calendar did Adriana buy?
Mathematics
2 answers:
solmaris [256]3 years ago
8 0

Answer: she bought 3 wall calender's and 5  desk calender's

Step-by-step explanation:i skip counted and tried to fit the numbers as like if i was buying them

Alex73 [517]3 years ago
7 0

Answer:

She bought 3 wall calendars and 5 desk calendars.

Step-by-step explanation:

3 wall calendars times 5 dollars equals 15 dollars so she has 5 dollars left to buy 5 desk callenders totalling 20 dollars and 8 calendars.

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A car rental company offers two plans for renting a car. Plan A: 40 dollars per day and 10 cents per mile Plan B: 65 dollars per
-Dominant- [34]
Difference between 60 and 45 is 15 so $15 in 10 cent would be 150 so 150 miles . Answer: you would need to drive more than 150 miles for plan b to save money:)
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(3,4) and (-5,6) <br><img src="https://tex.z-dn.net/?f=%283%2C4%29%20and%20%28-5%2C6%29%20" id="TexFormula1" title="(3,4) and (-
IceJOKER [234]
(3,4) and (-5,6) are "coordinate planes".

These appear in algebra and math when you're graphing. These coordinate planes consist of "x" and "y" (x,y). The x's (which are 3 and -5 in your situation) should be graphed accordingly using the x-axis and the y's (which are 4 and 6 in your situation) should be graph accordingly using the y-axis. 
3 0
3 years ago
Place the indicated product in the proper location on the grid.<br><br> (5c +2/3 )(5c -2/3 )
asambeis [7]
<span><u>Answer</u>
25c^2-4/9



<u>Explanation</u>
In this question you are expected to expand (5c+2/3)(5c-2/3)
(5c+2/3)(5c-2/3)=(5c×5c)-(5c×2/3)+(5c×2/3)-(2/3×2/3)
=25c^2-10c/3+10c/3-4/9
25c^2-4/9
The expanded form of (5c+2/3)(5c-2/3) is 25c^2-4/9 and this is what the question requires of you to do.</span>
3 0
4 years ago
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Why it take much longer time ghan the time calculated
mrs_skeptik [129]

Answer:

for what bro

Step-by-step explanation:

please mark me as brainlest

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3 years ago
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A distance AB is observed repeatedly using the same equipment and procedures, and the results, in meters, are listed below: 67.4
skad [1K]

Answer:

a) \bar X =\frac{67.401+67.400+67.402+67.396+67.406+67.401+67.396+67.401+67.405+67.404}{10}=67.401

b) The sample deviation is calculated from the following formula:

s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

And for this case after replace the values and with the sample mean already calculated we got:

s=0.0036

If we assume that the data represent a population then the standard deviation would be given by:

\sigma=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n}}

And then the deviation would be:

\sigma =0.00319

Step-by-step explanation:

For this case we have the following dataset:

67.401, 67.400, 67.402, 67.396, 67.406, 67.401, 67.396, 67.401, 67.405, and 67.404

Part a: Determine the most probable value.

For this case the most probably value would be the sample mean given by this formula:

\bar X =\frac{\sum_{i=1}^n X_i}{n}

And if we replace we got:

\bar X =\frac{67.401+67.400+67.402+67.396+67.406+67.401+67.396+67.401+67.405+67.404}{10}=67.401

Part b: Determine the standard deviation

The sample deviation is calculated from the following formula:

s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

And for this case after replace the values and with the sample mean already calculated we got:

s=0.0036

If we assume that the data represent a population then the standard deviation would be given by:

\sigma=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n}}

And then the deviation would be:

\sigma =0.00319

3 0
4 years ago
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