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3 years ago

What is the answer to this

Mathematics

2 answers:

Volgvan3 years ago

8 0

The answer to this is 142 .

ASHA 777 [7]3 years ago

6 0

Answer:

143

Step-by-step explanation:

38 degrees and m<7 equal 180 because they are supplementary angles so you do 180-38 to find your answer

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The diminsion on a sqare are doubled what happens to the area of the square

Alchen [17]

Answer:

the area is quadrupled.

8 0

2 years ago

What is the value of x? Enter your answer in the box.

mario62 [17]

X = 12

because if you notice, each of the angles have a little arc in the corner, which means they are congruent. if all three angles are congruent, that means each angle is 60° because each triangle has a maximum value of 180°. therefore, this means it is an equilateral triangle.

that being said, each side must be equal as well. so, you can use any two sides to find x by using each one on a different side of an equation, then isolating and solving.

5x - 22 = 3x + 2 = 4x - 10

so

5x - 22 = 3x + 2
3x + 2 = 4x - 10
4x - 10 = 5x - 22

whichever one you solve for, x = 12. and if you plug in that number for x, each side equals the same number = 38

8 0

3 years ago

Which equation shows the quadratic formula used correctly to solve 5x2 + 3x – 4 = 0 for x? x = StartFraction negative 3 plus-or-

Brrunno [24]

Answer: FIRST OPTION

Step-by-step explanation:

<h3> The missing picture is attached.</h3>

By definition, given a Quadratic equation in the form:

$ax^2+bx+c=0$

Where "a", "b" and "c" are numerical coefficients and "x" is the unknown variable, you caN use the Quadratic Formula to solve it.

The Quadratic Formula is the following:

$x=\frac{-b \±\sqrt{b^2-4ac} }{2a}$

In this case, the exercise gives you this Quadratic equation:

$5x^2 + 3x - 4 = 0$

You can identify that the numerical coefficients are:

$a=5\\\\b=3\\\\c= - 4$

Therefore, you can substitute values into the Quadratic formula shown above:

$x=\frac{-b \±\sqrt{b^2-4ac} }{2a}\\\\x=\frac{-3 \±\sqrt{(3)^2-4(5)(-4)} }{2(5)}$

You can identify that the equation that shows the Quadratic formula used correctly to solve the Quadratic equation given in the exercise for "x", is the one shown in the First option.

6 0

3 years ago

Read 2 more answers

The solution to the system equations

katovenus [111]

Let's solve this system of equations through substitution.

We have these two equations.

-7x-2y=14

6x+6y=18

Now let divide the second equation by 6.

6x+6y=18 ----> x+y=3

Next, let us move y to the right side of the equation.

x+y=3 -------> x=3-y (x equals 3-y)

Because we found out that what x is in terms of y, we can input that in for every instance of x in this equation below.

-7x-2y=14 becomes -7(3-y)-2y=14 (Why? Because x equals 3-y!)

We have a one variable equation now and can solve for y.

-7(3-y)-2y=14

-21+7y-2y=14

5y=35

y=7

Plug in 7 for y in any equation to find x.

x+y=3

x+7=3

x=-4

answer: x=-4, y=7

3 0

3 years ago

What value of n makes the equation true? (2x^9y^n)(4x^2y^10)=8x^11y^20

Komok [63]

Hi there! The answer is n = 10.

$(2 {x}^{9} {y}^{n} )(4 {x}^{2} {y}^{10} ) = 8 {x}^{11} {y}^{20}$

As you see at the powers of x, we need to add the exponents of the power we when multiply them.
${x}^{9} \times {x}^{2} = {x}^{9 + 2} = x {}^{11}$

The powers of y work the same way.
${y}^{n} \times {y}^{10} = {y}^{n + 10} = {y}^{20}$

Hence, n = 10, since
${y}^{10 + 10} = {y}^{20}$

8 0

3 years ago