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3 years ago

Which equation is equivalent to the equation 2x - 3y =3

Mathematics

2 answers:

bearhunter [10]3 years ago

8 0

I believe your correct answer will be y = 2/3x - 1

Nataliya [291]3 years ago

5 0

Add 3y to both sides
divide both sides by 2 ....3+3y
2
factor out the common term
(answer) 3(1+y)
-----
2
and your done

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A square napkin is folded in half on the diagonal and placed on the diameter of a round plate (see diagram below). If the folded

Crank

Answer:

$A=81(\pi-1)\ in^2$

Step-by-step explanation:

step 1

Find the area of the plate

The area of a circle is given by the formula

$A=\pi r^{2}$

we have

$r=18/2=9\ in$ ---> the radius is half the diameter

substitute

$A=\pi (9)^{2}\\A=81\pi\ in^2$

step 2

Find the area of the square napkin folded (is a half of the area of the square napkin)

we know that

The diagonal of the square is the same that the diameter of the plate

Applying Pythagorean theorem

$D^2=2b^2$

where

b is the length side of the square

we have

$D=18\ in$

substitute

$18^2=2b^2$

solve for b^2

$b^2=162\ in^2$ -----> is the area of the square

Divide by 2

$162/2=81\ in^2$

step 3

Find the area of the space on the plate that is NOT covered by the napkin

we know that

The area of the space on the plate that is NOT covered by the napkin, is equal to subtract the area of the square napkin folded (is a half of the area of the square napkin) from the area of the plate

$A=(81\pi-81)\ in^2$

simplify

$A=81(\pi-1)\ in^2$

8 0

3 years ago

Mr.willer wanted to donate 27cans of food to each of 8 food banks.Each of the 23 students in Mr.willers class donated 9 cans . H

Degger [83]

Mr.willer needs 216 cans because 27 vans times 8 banks equals 216 and 23 times 9 equals 207 so he would need 9 more cans

5 0

3 years ago

9/4 is between what two numbers

Debora [2.8K]

9/4 is between 2 and 3

3 0

3 years ago

Doesn't it say Odd integers, I'm quite confused.

dem82 [27]

What says odd integers???

4 0

3 years ago

Read 2 more answers

Solve for x: 5/x^2-4+2/x=2/x-2

IRINA_888 [86]

$\dfrac{5}{x^2 - 4} + \dfrac{2}{x} = \dfrac{2}{x - 2}$

$\dfrac{5}{(x + 2)(x - 2)} + \dfrac{2}{x} = \dfrac{2}{x - 2}$

$\dfrac{5}{(x + 2)(x - 2)} \times x(x + 2)(x - 2) + \dfrac{2}{x} \times x(x + 2)(x - 2) = \dfrac{2}{x - 2} \times x(x + 2)(x - 2)$

$5x + 2(x + 2)(x - 2) = 2x(x + 2)$

$5x + 2(x^2 - 4) = 2x^2 + 4x$

$5x + 2x^2 - 8 = 2x^2 + 4x$

$5x - 8 = 4x$

$x - 8 = 0$

$x = 8$

Now we look at the common denominator.

It is x(x + 2)(x - 2).

x cannot be zero, -2 or 2 because that would cause a zero in the denominator.

Since we get x = 8, and x = 8 does not have to be excluded from the domain, the answer is x = 8.

Answer: x = 8

6 0

3 years ago