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Lana71 [14]
3 years ago
13

Suppose that y varies inversely with x. Write a function that models the inverse function. X= 15 when y= 2

Mathematics
1 answer:
yulyashka [42]3 years ago
3 0
The answer to this question is B: <span>y = 30/x. I hoped I have helped you today!</span>
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Step-by-step explanation:

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Mike's biweekly salary is $2345.00. How much does he make<br> each week?
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Solve each system by elimination. -2x + 8y = -30 9x - 16y = 15
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2 years ago
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Show that the velocity of the particle at time t is given by v(t)=70t(3t2+8)2 .
RideAnS [48]

Question:

A particle moves along the x-axis so that its position at time t>0 is given by x(t)=\frac{t^2 -9}{3t^2 +8}

Show that the velocity of the particle at time t is given by v(t) = \frac{70t}{(3t^2 + 8)^2}

Answer:

v(t) = \frac{70t}{(3t^2 + 8)^2}

Step-by-step explanation:

Given

x(t)=\frac{t^2 -9}{3t^2 +8}

Required

Show that:

v(t) = \frac{70t}{(3t^2 +8)^2}

To calculate v(t), we use:

v(t) = x'(t)

So, we have:

x(t)=\frac{t^2 -9}{3t^2 +8}

Apply quotient rule

x'(t) = \frac{vu' - uv'}{v^2}

Where

u =t^2 - 9

v=3t^2 + 8

So:

u =t^2 - 9

u' = 2t

v=3t^2 + 8

v' = 6t

So, we have:

x'(t) = \frac{vu' - uv'}{v^2}

x'(t) = \frac{(3t^2 + 8) * 2t - (t^2 - 9) * 6t}{(3t^2 + 8)^2}

Expand the numerator

x'(t) = \frac{6t^3 + 16t - 6t^3 + 54t}{(3t^2 + 8)^2}

Collect like terms

x'(t) = \frac{6t^3 - 6t^3+ 16t  + 54t}{(3t^2 + 8)^2}

x'(t) = \frac{70t}{(3t^2 + 8)^2}

Recall that:

v(t) = x'(t)

v(t) = \frac{70t}{(3t^2 + 8)^2}

<em>Proved</em>

5 0
3 years ago
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