A is not a subset of B but B is a subset of A (that is can be found in A) that is B⊆A is correct
<h3>Set theory</h3>
Set is defined as the arrangement of elements. They can be represented using the venn diagram.
Given the following sets
U = {x: x is an integer and 2≤x≤10} = {3, 4, 5, 6, 7, 8, 9}
A = {x: 2x+1>7} = {x > 3}
B={x: x^2>20} = {x >± 20}
From the set, can see that A is not a subset of B but B is a subset of A (that is can be found in A) that is B⊆A is correct
Learn more on sets here: brainly.com/question/13458417
Answer: y = 90°
Step-by-step explanation:
55.30786941 = sin-1 (148/180) round to 55.3° angle x
34.69213059 = cos-1 (148/180) . round to 34.7° "angle z" at right
34.7 +55.3 = 90
Sum of All angles of the triangle = 180° 180 -90 = 90
If angle x is 55.7 and angle z is 34.7° Angle y must be 90°
Ratio of inscribed arcs = ratio of chord to diameter
Answer: 2
2x-7=11 X=9 set up the up the negative portion of solutions Set up the negative portion of the 2x - 7= - 11 x= -2 and then x = 9,-2
Step-by-step explanation:
Answer:
[see below]
Step-by-step explanation:
There are 0.001 grams in a milligram. (1,000 milligrams in a gram.)
The total dose should be 0.2 grams.
Hope this helps.
Answer:
Ada is correct.
Step-by-step explanation:
Problems with Naman:
Naman is supposed to follow PEMDAS, which is the order of operations, and stands for:
Parenthesis
Exponents (& Roots)
Multiplications
Division
Addition
Subtraction
~
The mistake: Naman moved +6 to the left and added it to the 2 located on the left side of the expression. You cannot do that, as it breaks the law of PEMDAS. On the other hand, Ada did the correct thing, which was to distribute 2 to all terms within the parenthesis (as one term in the parenthesis has a variable, and the other is a constant, meaning that they cannot be combined). This leads to Naman not doing the rest of the question correct.
Next, Ada correctly combined the two constants, which resulted in 0. 0 means nothing, therefore the placeholder is not needed. Therefore, 8x is the final answer.
