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2 years ago

If f(x) = x^2 - 3x + 1 over 2, determine f ( 4 ) .

1 answer:

7 0

F(x)=x^2-3x+1/2, if f(4)
Substitute x with 4, to get
f(x)=x^2-3x+1/2
f(4)=4^2-3(4)+1/2
f(4)=16-12+1/2
f(4)=4+1/2
f(4)=4 1/2 or 4.5. Hope it help!

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Determine the margin of error for a 90% confidence interval to estimate the population mean when s = 40 for the sample sizes bel

Ann [662]

Answer:

a) The margin of error for a 90% confidence interval when n = 14 is 18.93.

b) The margin of error for a 90% confidence interval when n=28 is 12.88.

c) The margin of error for a 90% confidence interval when n = 45 is 10.02.

Step-by-step explanation:

The t-distribution is used to solve this question:

a) n = 14

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 14 - 1 = 13

90% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 13 degrees of freedom(y-axis) and a confidence level of $1 - \frac{1 - 0.9}{2} = 0.95$ . So we have T = 1.7709

The margin of error is:

$M = T\frac{s}{\sqrt{n}} = 1.7709\frac{40}{\sqrt{14}} = 18.93$

In which s is the standard deviation of the sample and n is the size of the sample.

The margin of error for a 90% confidence interval when n = 14 is 18.93.

b) n = 28

27 df, T = 1.7033

$M = T\frac{s}{\sqrt{n}} = 1.7033\frac{40}{\sqrt{28}} = 12.88$

The margin of error for a 90% confidence interval when n=28 is 12.88.

c) The margin of error for a 90% confidence interval when n = 45 is

44 df, T = 1.6802

$M = T\frac{s}{\sqrt{n}} = 1.6802\frac{40}{\sqrt{45}} = 10.02$

The margin of error for a 90% confidence interval when n = 45 is 10.02.

3 0

2 years ago

The Greatest Common Factor of 90,33,54

yawa3891 [41]

3 is the GCF of 903,354

3 0

3 years ago

One of the tables shows a proportional relationship. Graph the line representing the proportional relationship from this table i

Mkey [24]

Answer:

Table C

Step-by-step explanation:

we know that

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form $y/x=k$ or $y=kx$

Find the value of the constant of proportionality in each table

Table A

For $x=-2, y=-4$ ------> $k=-4/-2=2$

For $x=-1, y=-3$ ------> $k=-3/-1=3$

This table has different values of k

therefore

the table A does not represent a proportional relationship

Table B

For $x=-2, y=-4$ ------> $k=-4/-2=2$

For $x=-1, y=-2$ ------> $k=-2/-1=2$

For $x=1, y=3$ ------> $k=3/1=3$

This table has different values of k

therefore

the table B does not represent a proportional relationship

Table C

For $x=-2, y=-4$ ------> $k=-4/-2=2$

For $x=-1, y=-2$ ------> $k=-2/-1=2$

For $x=1, y=2$ ------> $k=2/1=2$

For $x=2, y=4$ ------> $k=4/2=2$

This table has the same value of k

therefore

the table C represent a proportional relationship

Table D

For $x=-2, y=-4$ ------> $k=-4/-2=2$

For $x=-1, y=-2$ ------> $k=-2/-1=2$

For $x=1, y=2$ ------> $k=2/1=2$

For $x=2, y=6$ ------> $k=6/2=3$

This table has different values of k

therefore

the table D does not represent a proportional relationship

3 0

3 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=%5Csqrt%7B29-12%5Csqrt%7B5%7D" id="TexFormula1" title="\sqrt{29-12\sqrt{5}" alt="\sqrt{29-12\s

SSSSS [86.1K]

$\sqrt{29 \: - \: 12 \sqrt{5} }$

Factor the indicated expression:

$\sqrt{(3 \: - \: 2 \sqrt{5}) ^{2} }$

Simplified the index the root and also the exponent using the number 2.

$\boxed{ \bold{2 \sqrt{5} \: - \: 3}}$

<h3><em><u>MissSpanish</u></em> </h3>

6 0

1 year ago

Read 2 more answers

Fifteen less than twice a number is less than or equal to -23

lutik1710 [3]

I would think the answer is -16

but that's is what i think

5 0

3 years ago