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3 years ago

Given Alex’s credit history, consider how the bank will likely view him.

Business

1 answer:

scZoUnD [109]3 years ago

5 0

Answer:

High Risk

Low

Higher

Explanation:

I got just got them all right

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Schonhardt Corporation's relevant range of activity is 2,500 units to 5,500 units. When it produces and sells 4,000 units, its a

Vladimir [108]

Answer:

c $11,600

Explanation:

At 4,000 units the unit cost for the fixed manufacturing overhead is 2.90 dollars

We multiply it by 4,000 to know the total amount

$2.90 x 4,000 units = $ 11,600

These will be fixed cost thus, will not change when we produce between the relevant rage of 2,500 to 5,500 units

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3 years ago

When an interviewer introduces a new topic area, she is using a

Damm [24]

Answer:

D. Primary question

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3 years ago

Barry is a farmer who sells his farm produce to top who is the broker for the agriculture industry burying time often agree on a

fredd [130]

I am guessing it could be secondary market.

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3 years ago

Before the last presidential debates, 50% of registered votes indicated they were planning to vote for the incumbent president.

MAVERICK [17]

Answer:

a) H₀ : p = 0.5

$H_{a} : p > 0.5$

b) z = 2.0785

c) p - value = 0.0188

d) Our conclusion is that there has been a significant increase in the proportion of registered voters who are planning to vote for the incumbent president

Explanation:

Probability of those planning to vote for the incumbent president before the debate, P₀ = 50/100 = 0.5

a) The null and the alternative hypothesis

Let the null hypothesis be represented by $H_{0}$

and the alternative hypothesis be represented by $H_{a}$

H₀ : p = 0.5

$H_{a} : p > 0.5$

b) compute the test statistics

sample size, n = 1200

number of voters planning to vote for the incumbent president, x = 636

Probability of those planning to vote for the incumbent president in the selected sample:

$\bar{p} = x/n\\\bar{p} = 636/1200\\\bar{p} = 0.53$

Formula for the test statistic:

$z = \frac{\bar{p} - p_{0} }{\sqrt{\frac{p_{0}(1-p_{0} ) }{n} } }$

$z = \frac{0.53 - 0.5 }{\sqrt{\frac{0.5(1-0.5 ) }{1200} } }$

z = 2.0785

For $\alpha = 0.05\\$ , the critical value as checked from the normal table will be:

$z_{\alpha} = 1.645$

The P value for z > 2.0785

$P-value = P(z > 2.0785) \\P - value = \phi (-2.0785)\\P - value = 0.0188$

d) What do you conclude?

since $( z = 2.0785) > (z_{\alpha} = 1.645)$ , we will reject the null hypothesis.

Our conclusion is that there has been a significant increase in the proportion of registered voters who are planning to vote for the incumbent president

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3 years ago

A group of customers that a business decides to focus its marketing efforts and, ultimately, its products on is a _____. target

SVEN [57.7K]

Answer:

Target market!!

Explanation:

Hope this helps:)

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2 years ago