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3 years ago

Write the equation in spherical coordinates. (a) 4x2 − 3x + 4y2 + 4z2 = 0

1 answer:

6 0

4x^2-3x+4y^2+4z^2=0
here we shall proceed as follows:
x=ρcosθsinφ
y=ρsinθsinφ
z=ρcosφ
thus
4x^2-3x+4y^2+4z^2=
4(ρcosθsinφ)^2-3(ρcosθsinφ)+4(ρsinθsinφ)^2+4(ρcosφ)
but
ρ=1/4cosθsinφ

hence we shall have:
4x^2-3x+4y^2+4z^2
=1/4cosθsinθ(cosθ(4-3sinφ))+4sin^2(φ)

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Students at a local high school travel to school by car, bus, and bicycle. 1/5 of the 825 students Tavel by car, 48% of the stud

dezoksy [38]

Answer:

198 students walk to the local high school

Step-by-step explanation:

Total number students = 825

1/5 of the students travel by car

48% of the students travel by bus

0.08 of the students travel by bicycle

To find the number of students who wal to school we have to find the exact number of students who travel to school by car, bus and bicycle and subtract the result from the total number of students

Students who travel by car = 1/5×825

= 165 students

Students who travel by bus = 48% × 825

= 48/100 × 825

= 12/25 × 825

= 396 students

Students who travel by bicycle = 0.08 × 825

= 66

So now we add the results fo the equations above and subtract it from the total number of students to get the number of students that walk to school

Students that walk to school = 825 - (165 + 396 + 66)

= 825 - 627

= 198 students

Therefore 198 students walk to the local high-school

7 0

3 years ago

Please help me with the following (1-5)

Ivanshal [37]

$1. \: 405352 \: cm = 4.05352 \times {10}^{5} \: cm$

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2. 7.6352 x 10-3 kg ( This is scientific notation) [ If you want —> Standard notation]

7.6352 x 10^ -3 kg = 0.0076352 kg

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$3. \: \: 3.1 \times 10 ^{4} mm + 4.87 \times {10}^{5} \: mm \\ 0.31\times 10 ^{4} mm + 4.87 \times {10}^{5} \: mm \\ = 5.18 \times {10}^{5} \: mm$

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$4. \: \: (4.8 \times {10}^{5} \: km) \times (2.0 \times {10}^{3} \: km ) \\ = 9.6 \times {10}^{8} \: km$

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I hope I helped you^_^

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3 years ago

The average rate of a printer is 4 seconds per page. At this rate, how many pages will be

Ludmilka [50]

60 divided by 4 is 15 15 multiplied by 3 is 45 pages

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3 years ago

Please help! I just need the second question answered given the first is correct.

Nataliya [291]

Answer: 0.970 ??

Step-by-step explanation:

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3 years ago

Which equation correctly uses the law of cosines to solve for the missing side length of trianglepqr? 62 = p2 82 – 2(p)(8)cos(39

Evgesh-ka [11]

The equation that correctly uses the law of cosines to solve for the missing side length of trianglepqr is <u>8^2 = 7^2 +11^2 - 2(7)(11) cos <P</u>

<h3>The cosine rule formula</h3>

For us to use the cosine formula, an angle must be situated between two sides of the triangle.

According to the rule;

c^2 = a^2 + b^2 - 2ab cos C

From the given diagram, if cos<P is the reference angle, then;

a = 11

b = 7

c = 8

Substiute

8^2 = 7^2 +11^2 - 2(7)(11) cos <P

Hence the equation that correctly uses the law of cosines to solve for the missing side length of trianglepqr is <u>8^2 = 7^2 +11^2 - 2(7)(11) cos <P</u>

Learn more on law of cosine here: brainly.com/question/8288607

6 0

2 years ago