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sdas [7]
3 years ago
7

How do you find mode in data

Mathematics
2 answers:
Norma-Jean [14]3 years ago
6 0

Answer: The number which is repeated maximum times in the data is called the mode.

Step-by-step explanation: Mode is how many times a number is repeated. The number which is repeated maximum no. of times is the mode of the data.

For e.g. 2,3,5,4,4,6,9,1,0,4,7,4

The mode of the data is 4 because it is repeated maximum times.

nikdorinn [45]3 years ago
4 0

Answer:

The mode is the number that shows up most frequently

Step-by-step explanation:

Example, in the number set below

1, 1, 2, 3, 4, 4, 4, 4, 5, 7, 35, 36

The mode is 4

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Determine the value<br> of x in this polygon. (PLATO)
tresset_1 [31]

Answer:

136

Step-by-step explanation:

No matter what the distribution, all of the interior angles of a convex hexagon will add up to 720 degrees. Therefore, if you subtract all of the known angles in this hexagon from 720, you will find x.

720-134-106-117-119-108=136 degrees. Hope this helps!

3 0
3 years ago
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635% at a mixed number
Stells [14]

Answer:

6 35/100 or six and 35 of 100

Step-by-step explanation:

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2 years ago
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N/2+5=3 what does n equal?
erica [24]

Answer:

n=-4

Step-by-step explanation:

n/2+5=3

n/2=-2

n=-4

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2 years ago
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QUESTION 3 [10 MARKS] A bakery finds that the price they can sell cakes is given by the function p = 580 − 10x where x is the nu
Andru [333]

Answer:

(a)Revenue=580x-10x²,

Marginal Revenue=580-20x

(b)Fixed Cost, =900

Marginal Cost,=300+50x

(c)Profit Function=280x-900-35x²

(d)x=4

Step-by-step explanation:

The price, p = 580 − 10x where x is the number of cakes sold per day.

Total cost function,c = (30+5x)²

(a) Revenue Function

R(x)=x*p(x)=x(580 − 10x)

R(x)=580x-10x²

Marginal Revenue Function

This is the derivative of the revenue function.

If R(x)=580x-10x²,

R'(x)=580-20x

(b)Total cost function,c = (30+5x)²

c=(30+5x)(30+5x)

=900+300x+25x²

Therefore, Fixed Cost, =900

Marginal Cost Function

This is the derivative of the cost function.

If c(x)=900+300x+25x²

Marginal Cost, c'(x)=300+50x

(c)Profit Function

Profit, P(x)=R(x)-C(x)

=(580x-10x²)-(900+300x+25x²)

=580x-10x²-900-300x-25x²

P(x)=280x-900-35x²

(d)To maximize profit, we take the derivative of P(x) in (c) above and solve for its critical point.

Since P(x)=280x-900-35x²

P'(x)=280-70x

Equate the derivative to zero

280-70x=0

280=70x

x=4

The number of cakes that maximizes profit is 4.

5 0
2 years ago
What fraction must be subtracted from the sum of 1/4 and 1/6 to have an average of 1/12 of all the two fractions
DanielleElmas [232]

Answer:

so 1/3 must be subtracted from the sum of 1/4 and 1/6 to have an average of 1/12 of all the two fractions.

Step-by-step explanation:

let the fraction be x

(1/4 + 1/6)-x =  1/12

or, 10/24 - x = 1/12

or, 5/12-1/12 = x

so, x = 4/12 = 1/3

8 0
2 years ago
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