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Aleksandr-060686 [28]
3 years ago
14

Determine the standard form of the equation of the line that passes through (-5,0) and (0,-9)

Mathematics
2 answers:
bonufazy [111]3 years ago
5 0

Answer:

9x+5y=-45

Step-by-step explanation:

To write the equation of a line we must have a slope and a point. To find the slope we use the slope formula and substitute (x,y) points in it as shown below:

m=\frac{y_2-y_1}{x_2-x_1}=\frac{-9-0}{0--5}=\frac{-9}{0+5}=\frac{-9}{5}=\frac{-9}{5}

Now that we have the slope, plug in the slope and choose one point to plug into the point slope formula. Use the point-slope form to write the equation, then simplify and convert into the slope intercept form.

(y-0)=-9/5(x--5)

y=-9/5(x+5)

y=-9/5x-9

Now convert to standard form, Ax+By=C.

y=-9/5x-9

9/5x+y=-9

9x+5y=-45



Alexeev081 [22]3 years ago
5 0

Hello there,

Determine the standard form of the equation of the line that passes through (-5,0) and (0,-9)

Answer: 9x+5y=-45


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What is two and two fourths plus one third
kkurt [141]

Answer:

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The mean SAT score in mathematics, M, is 600. The standard deviation of these scores is 48. A special preparation course claims
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Answer:

Step-by-step explanation:

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The test then boils down to the question if the score of 613 obtained by the students in the sample is statistically bigger that the "true" mean of 600.

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The test statistic for this type of test takes the form

t=\frac{| \mu -\bar x |} {\sigma/\sqrt{n}}

and this test statistic follows a normal distribution. This last part is quite important because it will tell us where to look for the critical value. The problem ask for a 0.05 significance level. Looking at the normal distribution table, the critical value that leaves .05% in the upper tail is 1.645.

With this we can then replace the values in the test statistic and compare it to the critical value of 1.645.

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Answer:

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= 17 divided 2

= 8.5

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