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2 years ago

If AC is 11 inches and BC is 4 inches, then AB

Mathematics

2 answers:

Nutka1998 [239]2 years ago

5 0

Answer:

11 - 4

Step-by-step explanation:

as u explain it to me now i know how to solve the question. because its a number line, its easy to imagine.

hope this helps <3

damaskus [11]2 years ago

3 0

11 - 4 because of the number line just minus

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Select ALL the correct answers.

Alona [7]

Income of the first account after x years:
$1,850(1.026)^x$
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$2,015(1.015)^x$
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$1,850(1.026)^x=2,015(1.015)^x$
Solving the above equation for x:
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Answer 8 years.

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3 years ago

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Is a half bigger then a third ?

Assoli18 [71]

1/2 plus 1/3 is 5/6.

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3 years ago

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Angie has to fill in a reading log for her English class. She is required to read a total of 10 and 5 over six hours a week. On

JulijaS [17]

Given:

She is required to read a total = $10\dfrac{5}{6}$ hours a week.

Monday she read $1\dfrac{1}{3}$ hours.

Tuesday she read $\dfrac{3}{4}$ of an hour.

Thursday she read 3 hours.

To find:

The total hours does she still need to read in order to get full credit.

Solution:

Total time = $10\dfrac{5}{6}$ hours a week.

Total time she already read $=1\dfrac{1}{3}+\dfrac{3}{4}+3$ hours

$=\dfrac{1\times 3+1}{3}+\dfrac{3}{4}+3$ hours

$=\dfrac{4}{3}+\dfrac{3}{4}+3$ hours

$=\dfrac{16+9+36}{12}$ hours

$=\dfrac{61}{12}$ hours

Now,

Remaining time = Total time - Total time she already read

$=10\dfrac{5}{6}-\dfrac{61}{12}$

$=\dfrac{65}{6}-\dfrac{61}{12}$

$=\dfrac{130-61}{12}$

$=\dfrac{69}{12}$

$=\dfrac{23}{4}$

$=5\dfrac{3}{4}$

Therefore, the required time is $5\dfrac{3}{4}$ hours.

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3 years ago

A bus travels 32 kilometers in 30 minutes. How far will the bus travel in 4 hours at that speed? Show your work.

timofeeve [1]

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2 years ago

N=4; 2i and 3i are zeros <br> f(-1)=50

Nonamiya [84]

Solution:- $\text{Let f(x) be any nth degree polynomial with n=4}\\$

$\text{Given that 2i and 3i are the zeroes of f(x)}$

$\text{so (x-2i) and (x-3i) are factors of f(x)}$

$\text{Since 2i is a zero of f(x) then its conjugate -2i is also a zero of f(x)}$

$\Rightarrow(x+2i) \text{is a factor}\\\text{Similarly, conjugate of 3i is -3i is also a zero of f(x) }\\\Rightarrow(x+3i)\text{is a factor}\\\text{So , }\\f(x)=k(x-2i)(x+2i)(x-3i)(x+3i)\\=k(x^2-(2i)^2)(x^2-(3i)^2)\\=k(x^2-4i^2)(x^2-9i^2)\\=k(x^2+4)(x^2+9)\\=k(x^4+13x^2+36)\\\text{As given}\\f(-1)=50\\\Rightarrow k((-1)^4+13(-1)^2+36)=50\\\Rightarrow k(1+13+36)=50\\\Rightarrow k(50)=50\\\Rightarrow k=1\\\text{So by substituting k=1 in f(x) we get ,}\\f(x)=(x^4+13x^2+36)$

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3 years ago