All categories

2 years ago

If AC is 11 inches and BC is 4 inches, then AB

Mathematics

2 answers:

Nutka1998 [239]2 years ago

5 0

Answer:

11 - 4

Step-by-step explanation:

as u explain it to me now i know how to solve the question. because its a number line, its easy to imagine.

hope this helps <3

damaskus [11]2 years ago

3 0

11 - 4 because of the number line just minus

You might be interested in

Let f(x) = 2x + 2. Solve f−1(x) when x = 4.

malfutka [58]

10 would be you best choice

4 0

3 years ago

Urgent please ans this

Rama09 [41]

Answer:

x=6

Step-by-step explanation:

Remember, the formula for area is the length times the width. So, if we know the width is 3, and we know the total area is 24, all we need to do is divide 24 by 3 to get 8. 8 is the split up side, the one that is x + 2. To find x, simply subtract 2 from 8. 8 - 2=6.

24/3=8

8-2=6

3 0

3 years ago

Suppose that, after measuring the duration of many telephone calls, a telephone company found their data was well-approximated b

Musya8 [376]

Answer:

a) 7.79%

b) 67.03%

c) Cumulative Distribution Function

$P(t) = \displaystyle\int^{\infty}_{-\infty} 0.1e^{-0.1t}~dt\\\\= \displaystyle\int^{b}_{a} 0.1e^{-0.1t}~dt, ~~a\leq t \leq b$

Step-by-step explanation:

We are given the following in the question:

$p(x) = 0.1 e^{-0.1x}$

where x is the duration of a call, in minutes.

a) P( calls last between 2 and 3 minutes)

$=\displaystyle\int^3_2 p(x)~ dx\\\\= \displaystyle\int^3_20.1e^{-0.1x}~dx\\\\=\Big[-e^{-0.1x}\Big]^3_2\\\\=-\Big[e^{-0.3}-e^{-0.2}\Big]\\\\= 0.0779\\=7.79\%$

b) P(calls last 4 minutes or more)

$=\displaystyle\int^{\infty}_4 p(x)~ dx\\\\= \displaystyle\int^{\infty}_40.1e^{-0.1x}~dx\\\\=\Big[-e^{-0.1x}\Big]^{\infty}_4\\\\=-\Big[e^{\infty}-e^{-0.4}\Big]\\\\=-(0- 0.6703)\\= 0.6703\\=67.03\%$

c) cumulative distribution function

$P(t) = \displaystyle\int^{\infty}_{-\infty} 0.1e^{-0.1t}~dt\\\\= \displaystyle\int^{b}_{a} 0.1e^{-0.1t}~dt, ~~a\leq t \leq b$

6 0

3 years ago

What is the value of n in this equation?<br>4^3×4^4=4n <br>

larisa [96]

4096
(4^3)(4^4) = 4n
16384 = 4n
4n = 16384
4n/4 = 16384/4
n = 4096

6 0

3 years ago

Read 2 more answers

Suppose a student started with 139.0 mg of trans-cinnamic acid, 463 mg of pyridinium tribromide, and 2.45 mL of glacial acetic a

Sliva [168]

Answer:

0.2889 g brominated product

64.6 %

Step-by-step explanation:

This is a bromination chemical reaction of an alkene and we are asked to calculate the theoretical and percent yield. Thus to solve it we have to perform a calculation based on the balanced chemical reaction.

The pyridinium tribromide is used as a generator of molecular bromine in situ, and bromine will add to the double bond in trans-cinnamic acid so we know the reaction occur in a one to one mole fashion.

trans-cinnamic acid + pyridinium tribromide ⇒ 2,3-dibromo-3-

phenylpropanoic acid

Molar weight trans-cinnamic acid = 148.16 g/mol

mass trans-cinnamic acid = 139.0 mg x 1g/1000 mg = 0.139 g

# mol trans-cinnamic acid = 0.139 g / 148 g/mol = 9.38 x 10⁻⁴ mol

Since our reaction is 1 mol trans-cinnamic acid produces 1 mol 2,3-dibromo-3-phenylpropanoic acid, it follows that the theoretical yield is:

1 mol 2,3-dibromo-3-phenylpropanoic acid / trans-cinnamic acid x 9.38 x 10⁻⁴ mol trans-cinnamic acid

= 9.38 x 10⁻⁴ mol 2,3-dibromo-3-phenylpropanoic acid

In grams the the theoretical yield is:

molar mass 2,3-dibromo-3-phenylpropanoic acid = 307.97 g/mol

The theoretical mass 2,3-dibromo-3-phenylpropanoic acid:

= 9.38 x 10⁻⁴ mol 2,3-dibromo-3-phenylpropanoic acid x 307.97 g/mol

= 0.2889 g

% yield = mass experimental/mass theoretical

= 0.1866 g / 0.2889 g x 100 = 64.6 %

4 0

3 years ago