Answer:
1.5
Step-by-step explanation:
The question is incomplete due to the probability distribution table, investigating you can find it so I will attach it.
Having the table, we need to find the mean of the probability distribution, which is defined as the sum of the product of probability and value of random distribution, that is:
M = Sum (xi) * P (xi)
We replace:
M = 0.5 * 0.07 + 1 * 0.2 + 1.5 * 0.46 + 2 * 0.2 + 2.5 * 0.07
M = 1.5
Therefore, the mean of the given table is 1.5
They consists of equations and unknown variables. There are 4 PCs and 8 Mac in the room
<h3>System of equation</h3>
They consists of equations and unknown variables
Let the number of PCs be x
Let the number of Mac be y
If Mke has 12 computers, then;
x + y = 12
If there are two Macs for every PC in his classroom, then;
y = 2x
Substitute
x + 2x = 12
3x = 12
x = 4
Recall y = 2x
y = 2(4)
y = 8
There are 4 PCs and 8 Mac in the room
Learn more on system of equations here; brainly.com/question/14323743
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Answer:

Step-by-step explanation:





<span>f(x)=5x+3/6x+7
This means that f(6/x) = [</span>5(6/x)+3] / [6(6/x)+7] = [ 30/x +3 ] / [36/x +7]
If we assume x≠0 , f(6/x) = [30 +3x]/ [36 + 7x]
g(x)=√<span> [ x^2-4x ]
</span>
g(x-4) = √ [ (x-4)^2-4(x-4) ] = √ [ x² -8x +16 -4x +16 ] = √ [ x^2-12x +32]
It would probably be B because it said between -30 and 130