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swat32
3 years ago
11

One letter is selected from the word "statistics." What is the probability that an "s" or "t" is chosen?

Mathematics
1 answer:
Pavel [41]3 years ago
5 0

Answer:

3/5

Step-by-step explanation:

There are 10 letters in the word "statistics".

Out of which, there are 3 s's and 3 t's.  

So, the question asks what's the probability to get a S or a T out of 10 letters.

Since the number of S's (3) and the number of T's equal 6, that means you have 6 chances out of 10 to pick an S or a T.

6/10 or if we simplify/reduce it... we get 3/5.

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I am extremely confused about the length of line segment AB. Could I get some help? (I have attached an image to this post)
Evgen [1.6K]

Answer:

The length of line segment AB is 9 units.

Step-by-step explanation:

To find this, you count how many squares there are between the two points. Hope I helped.

7 0
4 years ago
the relationship between feet and inches is a function. Write an equation that shows how to find the number of inches (n, output
BigorU [14]

Answer: One foot = 12in. Two Feet = 24in. Three Feet = 36in. Four Feet = 48in.


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7 0
3 years ago
Read 2 more answers
Sandra​, who is paid​ time-and-a-half for hours worked in excess of 40​ hours, had gross weekly wages of $ 608 or 56 hours worke
vodomira [7]
Time-and-a-half doesn't make enough sense to answer the question. If you fix it, or comment below the correction I will gladly help.
4 0
4 years ago
Solving for matrices
muminat

Answer:

D

Step-by-step explanation:

The augmented matrix for the system of three equaitons is

\left(\begin{array}{ccccc} 3&-4&-5&|&-27\\5&2&-2&|&11\\5&-4&4&|&-7\end{array}\right)

Multiply the first row by 5, the second row by -3 and add these two rows:

\left(\begin{array}{ccccc} 3&-4&-5&|&-27\\0&-26&-19&|&-168\\5&-4&4&|&-7\end{array}\right)

Subtract the third row from the second:

\left(\begin{array}{ccccc} 3&-4&-5&|&-27\\0&-26&-19&|&-168\\0&6&-6&|&18\end{array}\right)

Divide the third row by 6:

\left(\begin{array}{ccccc} 3&-4&-5&|&-27\\0&-26&-19&|&-168\\0&1&-1&|&3\end{array}\right)

Now multiply  the third equation by 26 and add it to the second row:

\left(\begin{array}{ccccc} 3&-4&-5&|&-27\\0&-26&-19&|&-168\\0&0&-45&|&-90\end{array}\right)

You get the system of three equations:

\left\{\begin{array}{r}3x-4y-5z=-27\\-26y-19z=-168\\-45z=-90\end{array}\right.

From the third equation

z=\dfrac{90}{45}=2.

Substitute z=2 into the second equation:

-26y-19\cdot 2=-168\\ \\-26y-38=-168\\ \\-26y=-168+38=-130\\ \\y=\dfrac{130}{26}=5.

Now substitute z=2 and y=5 into the first equation:

3x-4\cdot 5-5\cdot 2=-27\\ \\3x-20-10=-27\\ \\3x-30=-27\\ \\3x=-27+30=3\\ \\x=1.

The solution is (1,5,2)

4 0
3 years ago
The Fahrenheit and Celsius scales are related by the equation F=9/5C+32. What temperature is equal to a body temperature of 98.6
____ [38]

\textbf{Substitute\ in\ the\ equation}

\displaystyle 98.6 = \frac{9C}{5} +32

\textbf{Solve\ for\ }C

\displaystyle 66.6 = \frac{9C}{5}

333=9C

\large C=\textbf{37 \textdegree C}

7 0
2 years ago
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