Y varies directly with x , and x=3 when y=16 . What is x when y=40

Which statement about these two triangles is true?

Feliz [49]

It is th top right answer because AB = DE but the others are not but length doesn't effect the angles of abcdef

8 0

3 years ago

Question

Alekssandra [29.7K]

Answer:

Step-by-step explanation:

Given : Raymond wants to estimate the percentage of parents that use cloth diapers. He asks a randomly selected group of 200 parents whether or not they use cloth diapers.

The parameter are the number which are used to represents the quantity of a particular characteristic in entire population.

We know that to estimate the percentage of success we use the proportion of success parameter "p".

Hence, the parameter here is "p" , the proportion of parents that use cloth diapers.

8 0

2 years ago

Read 2 more answers

Find the distance between <img src="https://tex.z-dn.net/?f=%5Cfrac%7B7%7D%7B12%7D" id="TexFormula1" title="\frac{7}{12}" alt="\

jek_recluse [69]

Answer:

5/36

Explanation:

Distance on a number line is basically difference between two numbers. So we subtract the two numbers. This can be solved on a calculator btw. 7/12 - √16/81 = 5/36.

3 0

2 years ago

Suppose that the length of a phone call in minutes is an exponential random variable with parameter λ = 1/ 8. If someone arrives

Elis [28]

Answer:

a) P=0.535

b) P=0.204

c) P=0.286

Step-by-step explanation:

The exponential distribution is expressed as

$F(x>t)=e^{-\lambda t}$

In this example, λ=1/8=0.125 min⁻¹.

a) The probability of having to wait more than 5 minutes

$F(x>5)=e^{-0.125*5}=e^{-0.625}=0.535$

b) The probability of having to wait between 10 and 20 minutes

$F(1020)=e^{-0.125*10}-e^{-0.125*20}\\\\F(10$

c) The exponential distribution is memory-less, so it is independent of past events.

If you have waited 5 minutes, the probability of waiting more than 15 minutes in total is the same as the probability of waiting 15-5=10 minutes.

$F(x>15|t^*=5)=F(x>15)/F(x>5)=\frac{e^{-0.125*15}}{e^{-0.125*5}}=e^{-0.125*(15-5)}\\\\ F(x>15|t^*=5)=e^{-0.125*(10)}=F(x>10)=0.286$

5 0

3 years ago

Draw a vector representing the course of a ship that goes 75 miles on a

Nat2105 [25]

Answer:

The answer is below

Step-by-step explanation:

We have a vector with a magnitude of 75 miles and a direction of 300 °.

To draw it, the first thing is to make a Cartesian plane, the first thing is to know in which quadrant it would be, 300 ° is in the fourth quadrant (270 ° - 360 °), that is, it would be 30 ° (300 ° - 270 °) with respect to to the y axis negative.

Knowing this angle, we calculate the value of x and y, knowing that the magnitude of the vector is 75 miles, that is, this value would be the hypotenuse.

The value on the x-axis can be calculated using the sine of the angle, like this:

sin 30 ° = x / 75

x = sin 30 ° * 75

x = 37.5

Now to calculate the value on the y-axis it would be by means of Pythagoras and it would be:

y ^ 2 = 75 ^ 2 - 37.5 ^ 2

y ^ 2 = 4218.75

y = 64.95, -64.95 because it must be located in the fourth quadrant

Which means that to draw the vector that we are asked to do, we must draw a point from origin (0,0) to (37.5, -64.95).

Then I leave a sketch of what it would be:

7 0

3 years ago