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Sindrei [870]
3 years ago
8

Is the square root of 9 less than 3.54

Mathematics
2 answers:
Leto [7]3 years ago
7 0

Answer:

yes

Step-by-step explanation:

the square root of 9 is 3 so 3.54>3

Liula [17]3 years ago
4 0

Answer:

yes

Step-by-step explanation:

You might be interested in
(549+56877)-(587+662)+649
Nostrana [21]

Answer:

58075

Step-by-step explanation:

(549+56877)-(587+662)+649

57526 - 1249 + 1898= 58075

3 0
3 years ago
If y varies inversely as x and y = 9 when x = 4, find y when x = 6.
Rudiy27

Answer: x

=

6

Explanation:

the initial statement is

x

∝

1

y

to convert to an equation multiply by k the constant

of variation

⇒

x

=

k

×

1

y

=

k

y

to find k use the given condition

x

=

4

when

y

=

9

x

=

k

y

⇒

k

=

x

y

=

4

×

9

=

36

equation is

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

∣

∣

∣

2

2

x

=

36

y

2

2

∣

∣

∣

−−−−−−−−−−−−

when

y

=

6

then

x

=

36

6

=

6

Step-by-step explanation:

3 0
3 years ago
Jane wants to estimate the proportion of students on her campus who eat cauliflower. After surveying 24 ​students, she finds 2 w
irina1246 [14]

Answer:

A 95​% confidence interval for the proportion of students who eat cauliflower on​ Jane's campus is [0.012, 0.270].

Step-by-step explanation:

We are given that Jane wants to estimate the proportion of students on her campus who eat cauliflower. After surveying 24 ​students, she finds 2 who eat cauliflower.

Firstly, the pivotal quantity for finding the confidence interval for the population proportion is given by;

                              P.Q.  =  \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }  ~ N(0,1)

where, \hat p = sample proportion of students who eat cauliflower

           n = sample of students

           p = population proportion of students who eat cauliflower

<em>Here for constructing a 95% confidence interval we have used a One-sample z-test for proportions.</em>

<u>So, 95% confidence interval for the population proportion, p is ;</u>

P(-1.96 < N(0,1) < 1.96) = 0.95  {As the critical value of z at 2.5% level

                                                   of significance are -1.96 & 1.96}  

P(-1.96 < \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } } < 1.96) = 0.95

P( -1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } < {\hat p-p} < 1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ) = 0.95

P( \hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } < p < \hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ) = 0.95

Now, in Agresti and​ Coull's method; the sample size and the sample proportion is calculated as;

n = n + Z^{2}__(\frac{_\alpha}{2})

n = 24 + 1.96^{2} = 27.842

\hat p = \frac{x+\frac{Z^{2}__(\frac{\alpha}{2}_)  }{2} }{n} = \hat p = \frac{2+\frac{1.96^{2}   }{2} }{27.842} = 0.141

<u>95% confidence interval for p</u> = [ \hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } , \hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ]

 = [ 0.141 -1.96 \times {\sqrt{\frac{0.141(1-0.141)}{27.842} } } , 0.141 +1.96 \times {\sqrt{\frac{0.141(1-0.141)}{27.842} } } ]

 = [0.012, 0.270]

Therefore, a 95​% confidence interval for the proportion of students who eat cauliflower on​ Jane's campus [0.012, 0.270].

The interpretation of the above confidence interval is that we are 95​% confident that the proportion of students who eat cauliflower on​ Jane's campus is between 0.012 and 0.270.

7 0
2 years ago
How many centimeters are in 7.29 meters?
eimsori [14]
Multiply 7.29 meters by 100
Your answer is 729 centimeters
5 0
3 years ago
Read 2 more answers
Is this set of ratios equal?: 4/7 and 9/13
wel

Answer:

NO this set is not equivalent

Step-by-step explanation:

Okay the way you find out if a pair of ratios are equal is you would divide the denominator and nominator with each other, so: 13/7 and 9/4. But sense the answer would be in decimal form and cant be simplified this wouldnt be considered equivalent.  Also if you divide 7 by 4 you get a different answer than when you do 13 divided 9.

6 0
3 years ago
Read 2 more answers
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