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Degger [83]
3 years ago
5

Which number is the numerator in the fraction 1/2

Mathematics
1 answer:
Paraphin [41]3 years ago
5 0
1

a numerator in a fraction is the top number
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Which statement correctly compares functions fand g?
Irina18 [472]

Answer: the answer is A

Step-by-step explanation:

4 0
2 years ago
BRAINLIESTT ASAP! PLEASE HELP ME :)
Maslowich

Step-by-step explanation:

\displaystyle y = Asin(Bx - C) + D

According to this trigonometric function, −C gives you the OPPOSITE terms of what they really are, so be EXTREMELY CAREFUL:

\displaystyle Phase\:[Horisontal]\:Shift → \frac{0}{\frac{1}{7}} = 0 \\ Period → \frac{2}{1}π = 2π

Therefore we have our answer.

Extended Information on the trigonometric function

\displaystyle Vertical\:Shift → D \\ Phase\:[Horisontal]\:Shift → \frac{C}{B} \\ Period → \frac{2}{B}π \\ Amplitude → |A|

NOTE: Sometimes, your <em>vertical shift</em> might tell you to shift your graph below or above the <em>midline</em> where the amplitude is.

I am joyous to assist you anytime.

3 0
3 years ago
?????????????? help out
dimaraw [331]

Answer:

20 degrees C

Step-by-step explanation:

You would substitute the F with 68 since it is 68 degrees F. Then you would solve the equation. (Subtract 32 from 68=36; multiply 36 by 5/9=20)

5 0
3 years ago
consider the equations y=3x+7 and 5x+2y=3. Solve the system equations by graphing. Give your solution to the system as a pair of
alexandr402 [8]

Answer:

(1,4)

Step-by-step explanation:

The two lines intersect at 1,4 when you graph them

The first equation is already in slope intercept from, so you know the y-int. is 7 and the slope is 3. However, the second equation must be put in slope int. form.

5x+2y=3

move the y to the other side

5x=3-2y

move the 3 to the other side, so the y variable is by itself

5x-3=-2y

divide by -2 to the equation is equal to y

(-5x/2)+(3/2)=y

you now know the y int. of the second equation is 3/2 and the slope is -5/2

know that you know the slop int. formulas for both equations you can graph them

7 0
3 years ago
Question 15 (5 points)<br> Find the angle between u = &lt;7, -2&gt; and v= (-1,2&gt;.
Tema [17]

Answer:

Approximately 2.3127 radians, which is approximately 132.51^{\circ}.

Step-by-step explanation:

Dot product between the two vectors:

\begin{aligned}& u\cdot v \\ =\; & 7 \times (-1) + (-2) \times 2 \\ =\; & (-11) \end{aligned}.

Magnitude of the two vectors:

\begin{aligned} \| u \| &= \sqrt{{7}^{2} + {(-2)}^{2}} \\ &= \sqrt{53} \end{aligned}.

\begin{aligned} \| v \| &= \sqrt{{(-1)}^{2} + {2}^{2}} \\ &= \sqrt{5} \end{aligned}.

Let \theta denote the angle between these two vectors. By the property of dot products:

\begin{aligned} \cos(\theta) &= \frac{u \cdot v}{\|u\| \, \| v \|} \\ &= \frac{(-11)}{(\sqrt{53})\, (\sqrt{5})} \\ &= \frac{(-11)}{\sqrt{265}}\end{aligned}.

Apply the inverse cosine function {\rm arccos} to find the value of this angle:

\begin{aligned} \theta &= \arccos\left(\frac{u \cdot v}{\| u \| \, \| v \|}\right) \\ &= \arccos\left(\frac{(-11)}{\sqrt{265}}\right) \\ & \approx \text{$2.3127$ radians} \\ &= 2.3127 \times \frac{180^{\circ}}{\pi} \\ &\approx 132.51^{\circ}\end{aligned}.

8 0
2 years ago
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