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Degger [83]
3 years ago
5

Which number is the numerator in the fraction 1/2

Mathematics
1 answer:
Paraphin [41]3 years ago
5 0
1

a numerator in a fraction is the top number
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Evaluate 2d+3 when d =8
Snezhnost [94]

Answer:

19

Step-by-step explanation:

2(8) + 3

16 + 3

19

7 0
3 years ago
A car travels 2 5/8 miles in 3 1/2minutes at a constant speed. Which equation represents the distance, d, that the car travels i
kakasveta [241]

Answer:

Step-by-step explanation:

2⅝ miles/(3½ minutes) = (21/8 miles)/(7/2 minutes) = ¾ mile/minute

d = ¾m = 0.75m

8 0
2 years ago
One afternoon, a student who is 5 feet 4 inches tall measured shadows to find the height of a telephone pole. The student's shad
Setler79 [48]

Answer:

19.9875 feet

Step-by-step explanation:

The formula is given as:

Shadow of the student/Height of the student = Shadow of the telephone pole/Height of the telephone pole.

1 inch = 0.0833 feet

Shadow of the student = 5ft

Height of the student = 5 feet 4 inches

4 inches to feet

= 4 × 0.0833 feet

= 0.33 feet

Hence: Height of the student = 5 + 0.33 = 5.33 feet

Shadow of the telephone pole = 18 feet 9 inches long

9 inches to feet

= 9 × 0.0833 feet

= 0.75 feet

Hence: Shadow of the telephone pole = 18 + 0.75 = 18.75 feet

Height of the telephone pole= x

Therefore:

5/5.33 = 18.75/x

Cross Multiply

5x = 5.33 × 18.75

x = 5.33 × 18.75/5

x = 19.9875 feet

The height of the telephone pole = 19.9875 feet

4 0
3 years ago
Two cars traveling toward each other are 250 miles apart. Car a is traveling 15 miles per hour faster than car
Anon25 [30]

Let car  b be travelling at x  mph.  as they are travelling towards each other their speed of approach is (x + x + 15 ) mph.  So we have the equation

speed = distance / time

2x + 15 =  250 / 2

2x = 125 - 15 = 110

x = 55 mph

Car b travels at 55 mph and car a travels at 70 mph  Answer

3 0
3 years ago
If two of the four expressions x + y, x + 5y, x – y, and 5x – y are chosen at random, what is the probability that their product
storchak [24]

Answer:

  1/6

Step-by-step explanation:

The product will only be of the required form if the two chosen factors are of the form (x +by) and (x -by).

For the factor (x+y), there is also a factor (x-y) on the list. For the factor (x+5y), there is no factor (x-5y) available.

So, of the (4·3)/2 = 6 possible ways to choose two expressions from the four given expressions, only one pair of the 6 will have a product of the required form.

The probability is 1/6.

8 0
3 years ago
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