Answer: 0.3439
Step-by-step explanation:
Given :The last four digits for telephone numbers are randomly selected (with replacement).
Here , each position can be occupied with any of the digit independently .
Total digits = 10
Total digits other than 0 = 9
For each digits , the probability that it is not 0 = 
If we select 4 digits , The probability of getting no 0 =
(By multiplication rule of independent events)
Now , the probability that for one such phone number, the last four digits include at least one 0. = 1- P(none of them is 0)
=1- 0.6561=0.3439
Hence, the probability that for one such phone number, the last four digits include at least one 0. is 0.3439 .
50% so 9/18, or 1/2 simplified
Answer:
20%
Step-by-step explanation:
It would be equivalent to 18/22 as double 11 is 22 so we just do the same to the numerator (double)
Answer:
50-2
Step-by-step explanation:
there is 50 donuts and 2 that are frosted :)