mrs peters bought 7 1/2 yards of fabric she needs another 4 7/8 yards how many yards of fabric does she need altogether

A seal is swimming in the ocean 5 feet below sea level. It dives down 12 feet to catch

Bond [772]

The seals final elevation is 9 feet below sea level.

5 0

3 years ago

Which of the following is an extraneous solution of StartRoot 4 x + 41 EndRoot = x + 5? x = –8 x = –2 x = 2 x = 8

Finger [1]

Answer:

-8

Step-by-step explanation:

when you solve for x you get -8 but when you pkug it back in both sides are not equal, making it extranious

5 0

2 years ago

Read 2 more answers

Helpppppppp please it’s due today

yanalaym [24]

Answer:

Option B, would be the correct option as she sets it in the attic window. I hope this helps you! :)

8 0

2 years ago

Whiskers the cat weighs 2 2/3 kg. Piglo weighs 4kg. For each question , write a myipulcation and a division equation, decide whe

Liula [17]

Answer:

1) x= 3/2= 1 1/2

2) x= 2/3

Step-by-step explanation:

1)How many times as heavy as Whiskers is Piglio?

a) Write a multiplication equation for the question.

2 2/3 kg * [x]= 4kg

b) Write a division equation for the question.

4/ 2 (2/3) = x

c) Is the answer greater than 1 or less than 1?

Ans) Greater than 1

d) Find the answer

4/ 8/3= x

x= 3/2= 1 1/2

Pigilo is 1 1/2 times as heavy as whiskers

2)How many times as heavy as Piglio is Whiskers?

a) Write a multiplication equation for the question.

4 kg * [x]= 2 2/3 kg

b) Write a division equation for the question.

2 (2/3)/4 = x

c) Is the answer greater than 1 or less than 1?

Ans) Less than 1

d) Find the answer

8/3/4= x

8/3 * 1/4= x

2/3= x

Whiskers is 2/3 times as heavy as Pigilo.

5 0

2 years ago

A survey reported in Time magazine included the question ‘‘Do you favor a federal law requiring a day waiting period to purchase

il63 [147K]

Answer:

The 90% confidence interval for the difference between proportions is (-0.260, -0.165).

Step-by-step explanation:

The question is incomplete. The complete question is:

"A survey reported in Time magazine included the question ‘‘Do you favor a federal law requiring a 15 day waiting period to purchase a gun?” Results from a random sample of US citizens showed that 318 of the 520 men who were surveyed supported this proposed law while 379 of the 460 women sampled said ‘‘yes”. Use this information to find a 90% confidence interval for the difference in the two proportions, pm - pw. Subscript pm is the proportion of men who support the proposed law and pw is the proportion of women who support the proposed law. (Round answers to 3 decimal places.)"

We want to calculate the bounds of a 90% confidence interval.

For a 90% CI, the critical value for z is z=1.645.

The sample of men, of size nm=-0.26 has a proportion of pm=0.612.

$p_m=X_m/n_m=318/520=0.612$

The sample 2, of size nw= has a proportion of pw=0.824.

$p_w=X_w/n_w=379/460=0.824$

The difference between proportions is (pm-pw)=-0.212.

$p_d=p_m-p_w=0.612-0.824=-0.212$

The pooled proportion, needed to calculate the standard error, is:

$p=\dfrac{X_m+X_w}{n_m+n_w}=\dfrac{318+379}{520+460}=\dfrac{697}{980}=0.711$

The estimated standard error of the difference between means is computed using the formula:

$s_{pm-pw}=\sqrt{\dfrac{p(1-p)}{n_m}+\dfrac{p(1-p)}{n_w}}=\sqrt{\dfrac{0.711*0.289}{520}+\dfrac{0.711*0.289}{460}}\\\\\\s_{pm-pw}=\sqrt{0.00039+0.00045}=\sqrt{0.001}=0.029$

Then, the margin of error is:

$MOE=z \cdot s_{pm-pw}=1.645\cdot 0.029=0.0477$

Then, the lower and upper bounds of the confidence interval are:

$LL=(p_1-p_2)-z\cdot s_{p1-p2} = -0.212-0.0477=-0.260\\\\UL=(p_1-p_2)+z\cdot s_{p1-p2}= -0.212+0.0477=-0.165$

The 90% confidence interval for the difference between proportions is (-0.260, -0.165).

6 0

2 years ago