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2 years ago

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Mathematics

1 answer:

dezoksy [38]2 years ago

8 0

3 x 3 x 3 = 27 + 1 = 28 ÷ 7 = 4 x 2 = 8 + 5 x 8 = 48

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What is the equation of the line that is perpendicular to the given line and passes through the point (3, 0)?

olga2289 [7]

Step $1$

Find the slope of the given line

Let

$A(-3,2)\ B(2,-1)$

slope mAB is equal to

$mAB=\frac{(y2-y1)}{(x2-x1)} \\ \\ mAB=\frac{(-1-2)}{(2+3)} \\ \\ mAB=-\frac{3}{5}$

Step $2$

Find the slope of the line that is perpendicular to the given line

Let

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we know that

If two lines are perpendicular, then the product of their slopes is equal to $-1$

$mAB*mCD=-1\\ mAB=-\frac{3}{5} \\ mCD=-\frac{1}{mAB} \\ mCD=\frac{5}{3}$

Step $3$

Find the equation of the line with mCD and the point (3,0)

we know that

the equation of the line in the form point-slope is equal to

$y-y1=m(x-x1)\\\\ y-0=\frac{5}{3} *(x-3)\\\\ y=\frac{5}{3} x-5$

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$3y=5x-15$

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therefore

the answer is

the equation of the line that is perpendicular to the given line is the equation $5x-3y=15$

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sattari [20]

Answer:

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Step-by-step explanation:

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01:36:08

Angelina_Jolie [31]

Answer:

check online for more information

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