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ser-zykov [4K]
3 years ago
8

Which ordered pair is a solution of this equation -x-y = 6

Mathematics
2 answers:
Alex17521 [72]3 years ago
8 0

Answer:

(-4,-2)

Step-by-step explanation:

Plug the numbers in to the equation.

So,

-(-4) - (-2) = 6

Since a double negative equals a positive,

4 + 2 = 6


VLD [36.1K]3 years ago
4 0

Answer:

(-4,-2)

Step-by-step explanation:

This is because two negatives make a positive. When adding 4 and 2 is 6 hence thats the answer.

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7=x1

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Just plug in the missing values into the equation and solve the equation :)

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Read 2 more answers
The graph of y = x^2 -3 is translated in 4 units to the left of the graph to give the graph A
Vedmedyk [2.9K]

Answer:

a) b = 8, c = 13

b) The equation of graph B is y = -x² + 3

Step-by-step explanation:

* Let us talk about the transformation

  • If the function f(x) reflected across the x-axis, then the new  function g(x) = - f(x)
  • If the function f(x) reflected across the y-axis, then the new  function g(x) = f(-x)
  • If the function f(x) translated horizontally to the right  by h units, then the new function g(x) = f(x - h)
  • If the function f(x) translated horizontally to the left  by h units, then the new function g(x) = f(x + h)

In the given question

∵ y = x² - 3

∵ The graph is translated 4 units to the left

→ That means substitute x by x + 4 as 4th rule above

∴ y = (x + 4)² - 3

→ Solve the bracket to put it in the form of y = ax² + bx + c

∵ (x + 4)² = (x + 4)(x + 4) = (x)(x) + (x)(4) + (4)(x) + (4)(4)

∴ (x + 4)² = x² + 4x + 4x + 16

→ Add the like terms

∴ (x + 4)² = x² + 8x + 16

→ Substitute it in the y above

∴ y = x² + 8x + 16 - 3

→ Add the like terms

∴ y = x² + 8x + 13

∴ b = 8 and c = 13

a) b = 8, c = 13

∵ The graph A is reflected in the x-axis

→ That means y will change to -y as 1st rule above

∴ -y = (x² - 3)

→ Multiply both sides by -1 to make y positive

∴ y = -(x² - 3)

→ Multiply the bracket by the negative sign

∴ y = -x² + 3

b) The equation of graph B is y = -x² + 3

4 0
3 years ago
To which subset of real numbers does the number one-fourth belong? (1 point)
Trava [24]
It belongs to Q, The st of RATIONAL NUMBERS. It's written in terms of set:

1/4 ∈ Q={1/4, I 1∈Z, q∈Z, with q≠0}
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