Answer: She bought 6 $5 magazines and 5 $4 magazines
Step-by-step explanation:
Can you maybe take a picture of the problem, it’s kinda hard to understand what you’re trying to ask for
Answer: The wingspan is 36 m.
Using a proportion to solve this, we write the scale factor as a ratio first: 19/38, since 19 is the size of the model's length and 38 is the real length. For the second ratio, we have 18 for the size of the model wingspan and x for the real wingspan:
19/38 = 18/x
Cross multiply:
19*x = 38*18
19x = 684
Answer:
And we can find this probability with this difference and using the normal standard table:
Then the answer would be approximately 55.3% of women between the specifications. And that represent more than the half of women
Step-by-step explanation:
Let X the random variable that represent the weights of a population, and for this case we know the distribution for X is given by:
Where
and
We are interested on this probability
And the best way to solve this problem is using the normal standard distribution and the z score given by:
If we apply this formula to our probability we got this:
And we can find this probability with this difference and using the normal standard table:
Then the answer would be approximately 55.3% of women between the specifications. And that represent more than the half of women