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Bad White [126]
3 years ago
13

Determine which of the cross section shapes are possible for a right rectangular pyramid,where the length and width of the base

are not equal.
Select all that apply
A)Circle
B)Hexagon
C)rectangle
D)Square
E)Trapezoid
F)Triangle
Mathematics
1 answer:
Pachacha [2.7K]3 years ago
3 0
C)Rectangle, E)Trapezoid, F)Triangle
These shapes' cross sections have the length and width of their bases which are not equal
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*BRAINIEST &amp; 20 POINTS*<br><br> !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
kondor19780726 [428]

Answer:

8 = x

y = 29

Step-by-step explanation:

4x + 17 = y + 20 because vertical angles theorem.

y + 20 = 5x + 9  because interior angles theorem.

4x + 17 = 5x + 9  because same side interior angles theorem.

Subtract 9 from both sides and subtract 4x from both sides.

8 = x

Plug 8 in for x and solve.

5 times 8 is 40, plus 9 equals 49. Subtract 20 from both sides and you get 29.

5(8) + 9 = y + 20

49 = y + 20

29 = y

I hope this helps!

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2 years ago
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tekilochka [14]

Answer:

b. x>1

Step-by-step explanation:

2/3+x/3>1

Multiply the inequality by 3 to get rid of the fractions

3(2/3+x/3)>1*3

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3 years ago
Rearrange the formula to make a the subject:<br> B = 1/2h(a+b)
Mkey [24]

Answer:

Step-by-step explanation:

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3 years ago
Evaluate<img src="https://tex.z-dn.net/?f=10%5E%7B6%7D" id="TexFormula1" title="10^{6}" alt="10^{6}" align="absmiddle" class="la
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121,000,000,000
this is because:
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3 years ago
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It would be -56, just multiply as normal

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