Centroid, orthocenter, circumcenter, and incenter are the four locations that commonly concur.
<h3>Explain about the concurrency of medians?</h3>
A segment whose ends are the triangle's vertex and the middle of the other side is called a median of a triangle. A triangle's three medians are parallel to one another. The centroid, also known as the point of concurrency, is always located inside the triangle.
The incenter of a triangle is the location where the three angle bisectors meet. The only point that can be inscribed into the triangle is the center of the circle, which is thus equally distant from each of the triangle's three sides.
Draw the medians BE, CF, and their intersection at point G in the triangle ABC. Create a line from points A through G that crosses BC at point D. We must demonstrate that AD is a median and that medians are contemporaneous at G since AD bisects BC (the centroid)
To learn more about concurrency of medians refer to:
brainly.com/question/14364873
#SPJ4
Answer:
Hi there again!! the answer wold be 1 5/6.
Step-by-step explanation:
First subtract 9 by 7. The answer is 2. Now we have 1/6 of a bag eaten, which means there is 5/6 left. But we only have 1 bag left because 5/6 is the second bag. So the answer is 1 5/6!
Please mark me Brainliest! Thank you and have a nice day!
Answer: 3 (c)
Step-by-step explanation:
2 * 3 = 6 therefore 15 * 3 = 45$
3 * 2 = 6 therefore 21 * 2 = 42$
Answer:
A = l * w. We can substitute the expressions for length and width into the equation for area ... values in the formula for perimeter, we will get. P = 2l + 2w. P = 2(5)+2(3) P = 10+6 ... L = 18 cm. B = 7 cm. Perimeter of rectangle = 2(length + breadth) P = 2 (L + B) ... Total time taken = Total distance walked × time taken to walk 1m.
Simplify the following:
(3 + 1/3)/(2 + 2/5)
Put 2 + 2/5 over the common denominator 5. 2 + 2/5 = (5×2)/5 + 2/5:
(3 + 1/3)/((5×2)/5 + 2/5)
5×2 = 10:
(3 + 1/3)/(10/5 + 2/5)
10/5 + 2/5 = (10 + 2)/5:
(3 + 1/3)/((10 + 2)/5)
10 + 2 = 12:
(3 + 1/3)/(12/5)
Put 3 + 1/3 over the common denominator 3. 3 + 1/3 = (3×3)/3 + 1/3:
((3×3)/3 + 1/3)/(12/5)
3×3 = 9:
(9/3 + 1/3)/(12/5)
9/3 + 1/3 = (9 + 1)/3:
((9 + 1)/3)/(12/5)
9 + 1 = 10:
(10/3)/(12/5)
Multiply the numerator by the reciprocal of the denominator, (10/3)/(12/5) = 10/3×5/12:
(10×5)/(3×12)
The gcd of 10 and 12 is 2, so (10×5)/(3×12) = ((2×5) 5)/(3 (2×6)) = 2/2×(5×5)/(3×6) = (5×5)/(3×6):
(5×5)/(3×6)
3×6 = 18:
(5×5)/18
5×5 = 25:
Answer: 25/18
