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3 years ago

Which expression is equivalent to 6(a-3)? 18a 6(a)-6(3) 6(a)-3 3a

Mathematics

2 answers:

arsen [322]3 years ago

7 0

Answer:

Option 2

Step-by-step explanation:

6(a)-6(3)=6a-6×3=6(a-3)

Usimov [2.4K]3 years ago

7 0

Answer: 6(a)-6(3)

Step-by-step explanation:

$6(a-3)$ = $6a-18$

Let's check the first one, 18a which is not right. It's from 6(a)*3.

The second one is right, 6(a) = 6a and -6(3) = -18. Then we get 6a-18 which is right. then factor and get 6(a-3)

The third one is similar to the first one except 3 is in negative form (aka -3). But you get 6a-3 for the third one. factoring 6a-3 and you get 3(2a-1)

3a, no comment, it's from 3(a).

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Write in standard notation 6.12 x 10 to the 3rd power

faltersainse [42]

6.12 x 10^3 = 6120 .........<span> in standard notation
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3 years ago

Read 2 more answers

Which of the following is true with respect to the following functions:

Mkey [24]

The option that is true with regard to the following functions is Option B. "The domain g(x) and h(x) include all real number while the domain of i(x) and h(x) are restricted"

<h3>What is the explanation for the above?</h3>

Lets examine f(x) = 3x + 14

Note that this function is indicative of a straight-line. See the attached graph for function 1. Note that it doesn't have any end points. That is, it is Asymptote.

Let us examine h(x) = 3ˣ + 1

This represents an exponential graph. Just like the function above it doesn't have any end point. It however has an asymptote:

y = 0

Let us look at F'(x) = Log₃ (x = 1).

This is indicative of logarithm graph. It doesn't have any end but has an asymptote x == 0

Let us take a look at g(x) = X⁴ + 3x² - 14

Notice that in the mid point there is an end point given as (0, -14). Thus, it is correct to state that the function in Option B is the only one that exhibits end behavior and as such is restricted.

Learn more about functions:
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5 0

1 year ago

There are eight different jobs in a printer queue. Each job has a distinct tag which is a string of three upper case letters. Th

Vikentia [17]

Answer:

a. 40320 ways

b. 10080 ways

c. 25200 ways

d. 10080 ways

e. 10080 ways

Step-by-step explanation:

There are 8 different jobs in a printer queue.

a. They can be arranged in the queue in 8! ways.

No. of ways to arrange the 8 jobs = 8!

= 8*7*6*5*4*3*2*1

No. of ways to arrange the 8 jobs = 40320 ways

b. USU comes immediately before CDP. This means that these two jobs must be one after the other. They can be arranged in 2! ways. Consider both of them as one unit. The remaining 6 together with both these jobs can be arranged in 7! ways. So,

No. of ways to arrange the 8 jobs if USU comes immediately before CDP

= 2! * 7!

= 2*1 * 7*6*5*4*3*2*1

= 10080 ways

c. First consider a gap of 1 space between the two jobs USU and CDP. One case can be that USU comes at the first place and CDP at the third place. The remaining 6 jobs can be arranged in 6! ways. Another case can be when USU comes at the second place and CDP at the fourth. This will go on until CDP is at the last place. So, we will have 5 such cases.

The no. of ways USU and CDP can be arranged with a gap of one space is:

6! * 6 = 4320

Then, with a gap of two spaces, USU can come at the first place and CDP at the fourth. This will go on until CDP is at the last place and USU at the sixth. So there will be 5 cases. No. of ways the rest of the jobs can be arranged is 6! and the total no. of ways in which USU and CDP can be arranged with a space of two is: 5 * 6! = 3600

Then, with a gap of three spaces, USU will come at the first place and CDP at the fifth. We will have four such cases until CDP comes last. So, total no of ways to arrange the jobs with USU and CDP three spaces apart = 4 * 6!

Then, with a gap of four spaces, USU will come at the first place and CDP at the sixth. We will have three such cases until CDP comes last. So, total no of ways to arrange the jobs with USU and CDP three spaces apart = 3 * 6!

Then, with a gap of five spaces, USU will come at the first place and CDP at the seventh. We will have two such cases until CDP comes last. So, total no of ways to arrange the jobs with USU and CDP three spaces apart = 2 * 6!

Finally, with a gap of 6 spaces, USU at first place and CDP at the last, we can arrange the rest of the jobs in 6! ways.

So, total no. of different ways to arrange the jobs such that USU comes before CDP = 10080 + 6*6! + 5*6! + 4*6! + 3*6! + 2*6! + 1*6!

= 10080 + 4320 + 3600 + 2880 + 2160 + 1440 + 720

= 25200 ways

d. If QKJ comes last then, the remaining 7 jobs can be arranged in 7! ways. Similarly, if LPW comes last, the remaining 7 jobs can be arranged in 7! ways. so, total no. of different ways in which the eight jobs can be arranged is 7! + 7! = 10080 ways

e. If QKJ comes last then, the remaining 7 jobs can be arranged in 7! ways in the queue. Similarly, if QKJ comes second-to-last then also the jobs can be arranged in the queue in 7! ways. So, total no. of ways to arrange the jobs in the queue is 7! + 7! = 10080 ways

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3 years ago

What is the volume of a right cylinder<br> with a radius of 14 units and a height<br> of 31 units?

drek231 [11]

Answer:

6076π ≈ 19088.3 cubic units

Step-by-step explanation:

The volume of a cylinder is found using the formula ...

V = πr²h

For the given dimensions, the volume is ...

V = π(14²)(31) = 6076π ≈ 19088.3 . . . cubic units

4 0

2 years ago

Natali [406]

The area of the rectangle is the product of its base and height

The height of the rectangle is 4x - 2 units

<h3>How to determine the height?</h3>

The given parameters are:

Area = 4x^2 - 2x

Base = x

The area of the rectangle is:

Area = Base * Height

This gives

4x^2 - 2x = x * Height

Divide through by x

4x - 2 = Height

Rewrite as:

Height = 4x - 2

Hence, the height of the rectangle is 4x - 2 units