It is hard to comprehend your question. As far as I understand:
f(x,y) = e^(-x)
Find the volume over region R = {(x,y): 0<=x<=ln(6), -6<=y <= 6}.
That is all I understood. It would be easier to understand with a picture or some kind of visual aid.
Anyways, to find the volume between the surface and your rectangular region R, we must evaluate a double integral of f on the region R.

Now evaluate,

which evaluates to, 5/6 if I did the math correct. Correct me if I am wrong.
Now integrate this w.r.t. y:

So,

The answer to the problem is A
Mean is the same as the average
median is the middle number
mode is the number that is used most often
range is the highest number minus the lowest number
example :
2,3,3,5,7
u find the mean by adding up all the numbers, then dividing by how many numbers there are. (2 + 3 + 3 + 5 + 7) / 5 = 20/5 = 4 (the mean)
the median would be the middle number, and that would be 3
the mode would be the number that appears the most..that would be 3 because it appears twice.
the range is the highest - lowest : 7 - 2 = 5 (the range)...bur dont get this confused by the interquartile range..it is not the same as the range.
Answer:
9
Step-by-step explanation
Sqaure root of 9 is 3, a rational number