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yuradex [85]
3 years ago
12

On the first day of a measles outbreak at a school, 5 students were identified to have the measles. Each day for the following t

wo weeks, the number of new cases doubled from those identified with the disease the day prior.
How many students are identified to have measles in all at the end of the 6th day of the outbreak?



286

315

345

378
Mathematics
1 answer:
Snowcat [4.5K]3 years ago
8 0
If you interpret the question as is, the answer is in the thousands, which is not listed. The last part of the question should read 'the number of new cases doubled from those newly identified cases from the day prior. The question is very poorly phrased.

Day 1 : 5
Day 2: 5 + 10
Day 3: 15 + 20
Day 4: 35 + 40
Day 5: 75 + 80
Day 6: 155 + 160

Which is 315 at the end of 6th day
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Brooke plays on her schools softball team. Last season she was at bat 500 times and made a safe hit 28% of the time. How is 28%
Gre4nikov [31]

Answer:

28/100

Step-by-step explanation:

5 0
2 years ago
I JUST REALLY MEED HELP I GIVE BRAINLIEST
Nutka1998 [239]

Answer:

32 dollars

Step-by-step explanation:

Let's say the original price is x

Create an equation:

\frac{1}{2}x -5 = 11

Add 5 on both sides

\frac{1}{2}x = 16

x = 32

The answer is 32 dollars

Hope this helps :)

Have a nice day!

8 0
2 years ago
Find the numbers b such that the average value of f(x) = 7 + 10x − 9x2 on the interval [0, b] is equal to 8.
barxatty [35]

Answer:

The numbers b such that the average value of f(x) = 7 +10\cdot x - 9\cdot x^{2} on the interval [0, b] is equal to 8 are b_{1} \approx 1.434 and b_{2} \approx 0.232.

Step-by-step explanation:

The mean value of function within a given interval is given by the following integral:

\bar f = \frac{1}{b-a}\cdot \int\limits^b_a {f(x)} \, dx

If f(x) = 7 +10\cdot x - 9\cdot x^{2}, a = 0, b = b and \bar f = 8, then:

\frac{1}{b}\cdot \int\limits^b_0 {7+10\cdot x -9\cdot x^{2}} \, dx = 8

\frac{7}{b}\int\limits^b_0 \, dx  + \frac{10}{b}  \int\limits^b_0 {x}\, dx - \frac{9}{b}  \int\limits^b_0 {x^{2}}\, dx = 8

\left(\frac{7}{b} \right)\cdot b + \left(\frac{10}{b} \right)\cdot \left(\frac{b^{2}}{2} \right)-\left(\frac{9}{b} \right)\cdot \left(\frac{b^{3}}{3} \right) = 8

7 + 5\cdot b - 3\cdot b^{2} = 8

3\cdot b^{2}-5\cdot b +1 = 0

The roots of this polynomial are determined by the Quadratic Formula:

b_{1} \approx 1.434 and b_{2} \approx 0.232.

The numbers b such that the average value of f(x) = 7 +10\cdot x - 9\cdot x^{2} on the interval [0, b] is equal to 8 are b_{1} \approx 1.434 and b_{2} \approx 0.232.

7 0
3 years ago
I need help on this may you help
HACTEHA [7]

Answer:

should be 63

Step-by-step explanation:

6 0
1 year ago
I dont under stand these?
Alexeev081 [22]
The first one means what is the smallest number that goes into 12 which would be 4. The second one mean what does not go into 4 and 6 so that would be 8 because 6 is not a multiple of 8.The third one is either 1 or 2 not sure. And the 4th one is little complicated you might want to look up video on prime factorization that can really help you . 
8 0
3 years ago
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