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Tresset [83]
3 years ago
14

If you have 16 cups of sugar , 2 cups of sugar for every batch of cookies , but you have to save 6 cups of sugar for something e

lse . How many batches of cookies can you make?
Mathematics
1 answer:
sesenic [268]3 years ago
8 0
The first step we want to take here is to subtract 6 cups of sugar since we'll need it for something else, leaving us with 10 cups of sugar. It takes 2 cups of sugar for every batch of cookies, so you're going to divide 10 by 2. Luckily, 2 is a multiple of 10 so it's a whole number. By dividing, we get 5. So, we can make 5 batches of cookies while still saving 6 cups of sugar for something else.
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Mrs. Regan went shopping and purchased 37 trees for the yard. ​Mr. Regan also went shopping and bought some trees. ​ ​If they ha
VikaD [51]

Answer:

45 trees

Step-by-step explanation:

82=37+M m=mr.regan

-37. -37

45=M

5 0
3 years ago
PLEASE HELP ASAP! I don’t recall how to do this!
MakcuM [25]

Answer:

Step-by-step explanation:

For a. we start by dividing both sides by 200:

(1.05)^x=1.885

In order to solve for x, we have to get it out from its position of an exponent.  Do that by taking the natural log of both sides:

ln(1.05)^x=ln(1.885)

Applying the power rule for logs lets us now bring down the x in front of the ln:

x * ln(1.05) = ln(1.885)

Now we can divide both sides by ln(1.05) to solve for x:

x=\frac{ln(1.885)}{ln(1.05)}

Do this on your calculator to find that

x = 12.99294297

For b. we will first apply the rule for "undoing" the addition of logs by multipllying:

ln(x*x^2)=5

Simplifying gives you

ln(x^3)=5

Applying the power rule allows us to bring down the 3 in front of the ln:

3 * ln(x) = 5

Now we can divide both sides by 3 to get

ln(x)=\frac{5}{3}

Take the inverse ln by raising each side to e:

e^{ln(x)}=e^{\frac{5}{3}}

The "e" and the ln on the left undo each other, leaving you with just x; and raising e to the power or 5/3 gives you that

x = 5.29449005

For c. begin by dividing both sides by 20 to get:

\frac{1}{2}=e^{.1x}

"Undo" that e by taking the ln of both sides:

ln(.5)=ln(e^{.1x})

When the ln and the e undo each other on the right you're left with just .1x; on the left we have, from our calculators:

-.6931471806 = .1x

x = -6.931471806

Question d. is a bit more complicated than the others.  Begin by turning the base of 4 into a base of 2 so they are "like" in a sense:

(2^2)^x-6(2)^x=-8

Now we will bring over the -8 by adding:

(2^2)^x-6(2)^x+8=0

We can turn this into a quadratic of sorts and factor it, but we have to use a u substitution.  Let's let u=2^x

When we do that, we can rewrite the polynomial as

u^2-6u+8=0

This factors very nicely into u = 4 and u = 2

But don't forget the substitution that we made earlier to make this easy to factor.  Now we have to put it back in:

2^x=4,2^x=2

For the first solution, we will change the base of 4 into a 2 again like we did in the beginning:

2^2=2^x

Now that the bases are the same, we can say that

x = 2

For the second solution, we will raise the 2 on the right to a power of 1 to get:

2^x=2^1

Now that the bases are the same, we can say that

x = 1

5 0
3 years ago
There are 6 muffins in a package.How many packages will be needed to feed 48 people if each person has 2 muffins?
Paladinen [302]
16 packages would be needed



8 0
4 years ago
Read 2 more answers
What are the zeros for both functions
sammy [17]

Answer:

the zero of a function is the value of x which makes the final value zero

First Equation:

So let 25 - 2x equal to 0

<em>25 - 2x = 0</em>

x = 12.5

Second Equation:

Let 2x² - 11x - 6 equal to zero

<em>2x² - 11x - 6 = 0 </em>

<em>2x² - 12x + x - 6 = 0 </em><em>(Splitting the middle term)</em>

<em>2x(x - 6) + 1(x - 6) = 0</em>

<em>(2x + 1) (x - 6) = 0</em>

So we can transpose either one of the brackets below the zero

(2x + 1) = 0                 or             (x-6) = 0

x = -1/2                      or             x = 6

5 0
4 years ago
A French class has a total of
balu736 [363]

Their are 34 females in the class.

If 42 is the total amount of French students; subtract the amount of males(8) from the whole class to receive how many females their are in the class. Which is 34.

8 0
4 years ago
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